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kogti [31]
3 years ago
8

What is the value of the expression 4(80+ b) - 12, where b=20?

Mathematics
2 answers:
levacccp [35]3 years ago
7 0

Answer:

B. C which is the answer.

const2013 [10]3 years ago
3 0

Answer:

Step-by-step explanation:

c=388

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two sides of a parallelogram are 6.5 feet and 4.2 feet the measure of the angle between the sides 150° find the area of the para
Rudiy27
Yes that is correct both sides are right congratulations
3 0
3 years ago
Anyone know how to do this
zheka24 [161]
Y-2= -1/2(x+6)
Y-2= -1/2x - 3
Answer is:
Y= -1/2x -1
So your answer is A
4 0
3 years ago
What is the center of MN given M(3, -1) and N(7,-5)
Neko [114]

Answer:

(5, -3)

Step-by-step explanation:

So the center of the two points, or a line can be defined using the equation: midpoint=(\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2}). So using the two points you gave, you simply plug the values in to get

midpoint=(\frac{3+7}{2}, \frac{-1+(-5)}{2})\\

Add numerators:

midpoint=(\frac{10}{2}, \frac{-6}{2})

Simplify fraction:

midpoint=(5, -3)

3 0
2 years ago
Find the area of △ABC with side lengths b = 9 and c = 14, and included angle A = 145∘. Round your answer to the nearest tenth.
g100num [7]

Answer:

12 as well 45 78 u want to go 89

6 0
3 years ago
The mass of a radioactive substance follows a continuous exponential decay model, with a decay rate parameter of per day. Find t
jasenka [17]

Answer:

t = ln(0.5)/-r

Step-by-step explanation:

The decay rate parameter is missing. I will assume a value of 4% per day.

The exponential decay is modeled by the following equation:

A = A0*e^(-r*t)

where A is the mass after t time (in days), A0 is the initial mass and r is the rate (as a decimal).

At half-life A = A0/2, then:

A0/2 = A0*e^(-0.04*t)

0.5 = e^(-0.04*t)

ln(0.5) = -0.04*t

t = ln(0.5)/-0.04

t = 17.33 days

In general the half-life time is:

t = ln(0.5)/-r

3 0
3 years ago
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