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3 years ago

Juli went mining and found a large metal bar that weighed 20 kilos. After doing some analysis of the

Mathematics

1 answer:

masha68 [24]3 years ago

8 0

Answer:

8 kilos of it is gold, since 2/5 in decimal form is 0.40

12 kilos of it is copper.

Step-by-step explanation:

Multiply 20 times 0.40, you get 8, so 8 kilos of it is gold, while 12 kilos is copper.

T^T

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Select all the points that are on the graph of the line 2x + 3y = 6

Fudgin [204]

Answer:

The points are;

X Y

3 0

0 2

12 -6

15 -8

This is in no particular order.

Step-by-step explanation:

6 0

3 years ago

Three-tenths of the total volume, v, of water in a bucket spills. Which statement explains why 3/10x and 0.3x can each find the

ludmilkaskok [199]

Answer:

Answer: Multiplying by 3/10 is the same as multiplyinjg by 30%

8 0

3 years ago

The product of a number and negative two is the same as 5 less than the half the number. What is the equation the represents thi

snow_tiger [21]

Answer:

N(-2) = $\frac{n(-2)\\}{2}$ -5 this is also equal to n=2.5

Step-by-step explanation:

multiply both sides by 2

-4n = -2n-5

add 2n to both sides

-2n = -5

divide both sides by -2

n=2.5

3 0

3 years ago

Please answer ASAP!

romanna [79]

Answer:

volume is the product of the 3 dimensions. so devide the volume by the height and by the length to get just the width

1176 / 14 / 8

= 10.5

8 0

3 years ago

Please help with math problem

e-lub [12.9K]

Answer:

$a_0 = -8$

$a_1=-6$

$x^2 +y^2 -8x - 6y = 0$

Step-by-step explanation:

The equation of the circle has the following form

$x^2 + y^2 + a_0x + a_1y=0$

The equation of the circle has the following form

We know that the circle goes through the following points

(1, 7)

(8, 6)

(7, -1).

Then we substitute the values of x and y in the equation

$(1)^2 + (7)^2 + a_0(1) + a_1(7)=0$

$1 + 49 + a_0 + 7a_1=0$

$a_0 + 7a_1=-50$ (1)

$(8)^2 + (6)^2 + a_0(8) + a_1(6)=0$

$64 + 36 + 8a_0 + 6a_1=0$

$8a_0 + 6a_1= -100$ (2)

With these equations is enough to solve the system

$a_0 + 7a_1=-50$ (1)

$8a_0 + 6a_1= -100$ (2)

Multiply the equation (1) by -8 and add it to the equation (2)

$-8a_0 - 56a_1=400$ (1)

$8a_0 + 6a_1= -100$ (2)

-----------------------------------------------------

$-50a_1 = 300\\\\a_1 = -6$

Then

$a_0 + 7(-6) = -50\\\\a_0 = -50+42\\\\a_0=-8$

Finally the equation is:

$x^2 +y^2 -8x - 6y = 0$

7 0

3 years ago