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sasho [114]
3 years ago
7

What is the product

Mathematics
1 answer:
marysya [2.9K]3 years ago
7 0

Answer:30

Step-by-step explanation:

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100m world record was completed at an average speed of 37.6 km/h. work out this speed in meters per second?
pickupchik [31]

Step-by-step explanation:

1 km = 1000 m

1 hour = 3600 s

so,

37.6 km = 37,600 m (still per hour or per 3600 s).

in 1 second now that is

37600/3600 = 10.44444444... m/s

4 0
2 years ago
Wondering if anyone could help?
aleksklad [387]

Answer:

error

Step-by-step explanation:

4 0
3 years ago
Plss help me and explaim too​
masya89 [10]

Answer:

a = b = 1

Step-by-step explanation:

The triangles are similar thus ratios of corresponding sides are equal, that is

\frac{10}{2} = \frac{5}{b} ( cross- multiply )

10b = 10 ( divide both sides by 10 )

b = 1

and

\frac{10}{2} = \frac{5}{a} ( cross- multiply )

10a = 10 ( divide both sides by 10 )

a = 1

Thus a = 1 and b = 1

3 0
3 years ago
Finding angle measures using triangles
S_A_V [24]
Because HI and JK are parallel, that makes their angles congruent. So angle K equals angle I
So the interior angles of a triangle add up to 180°
So, Angle I + angle H + angle x =180°
60°+56°+x°=180°
116°+x°=180°
X=180-116
X=64°
6 0
3 years ago
You are in charge of managing the advertising for a restaurant. You are able to buy up to 62 advertisements a month, and your da
erik [133]

Answer:

Greatest number of newspaper ads = 59

Greatest number of television ads = 23

Step-by-step explanation:

It is given that we should buy at least 5 newspapers for every 3 television ads.

So, after purchasing 3 television ads, we can buy any number of television ads but the number should be greater than 5.

Since, the maximum is 62, we can buy 59 newspaper ads. (Note that we have already bought 3 television ads).

For every 3 television ads, we should buy 5 newspaper ads. So,

For the purchase of 3 television ads, we should buy the minimum of 5 newspaper ads.

For the purchase of 2(3) television ads, we should buy the minimum of 2(5) newspaper ads.

For the purchase of 3(3) television ads, we should buy the minimum of 3(5) newspaper ads.

...

...

For the purchase of 7(3) = 21 television ads, we should buy the minimum of 7(5) = 35 newspaper ads.

So, totally 21+35 = 56 ads.

For the remaining 6 ads, if we buy 3 television ads, we should buy 5 newspaper ads.

So, we can buy 2 television ads and 4 newspaper ads.

Hence, we can buy the maximum of 21+2 = 23 television ads.

7 0
3 years ago
Read 2 more answers
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