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Karolina [17]
3 years ago
12

Amber got a raise from $100 per week to $200 per week. What is the percent increase?

Mathematics
2 answers:
vivado [14]3 years ago
5 0

its a 100% increase since the amount completely doubled

hope this helps!!

Usimov [2.4K]3 years ago
3 0

Answer:

It is a 100% increase

Step-by-step explanation:

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Why is this correct?
Vanyuwa [196]

Answer: A= independent variable W = dependent variable  

Step-by-step explanation:

w= a/25

7 0
2 years ago
A local pizza shop has a membership program for frequent buyers. The membership costs $5 per month and members get a discounted
Len [333]

Answer: Nazim have to pay $35 for 20 slices of pizza.

Monthly cost for x slices =  5+1.5x

Step-by-step explanation:

Let x = number of slices

As per given,

Total monthly cost for x slices = (membership cost) +(discounted price) ×(x)

i.e. Total monthly cost for x slices = 5+1.5x

If x=20

Then, Nazim have to pay = 5+1.5(20)

= 5+30= $35

i..e Nazim have to pay $35 for 20 slices of pizza.

Monthly cost for x slices =  5+1.5x

5 0
2 years ago
An epidemiologist is observing the decay pattern of a pathogenic bacteria after applying a vaccine. He starts with 1,000 bacteri
Zielflug [23.3K]

Answer:

8%=1 hour

?=48 hours

48×8

384

1000-384

616 bacteria

6 0
3 years ago
Read 2 more answers
The graph of an exponential function passes through (1, 10) and (4, 80). Find the function that describes the graph.
svetlana [45]

Answer:

  • y = 5*2ˣ

Step-by-step explanation:

<u>Exponential function:</u>

  • y = abˣ

<u>Ordered pairs given:</u>

  • (1, 10) and (4, 80)

<u>Substitute x and y values to get below system:</u>

  • 10 = ab
  • 80 = ab⁴

<u>Divide the second equation by the first one and solve for b:</u>

  • 80/10 = b³
  • b³ = 8
  • b = ∛8
  • b = 2

<u>Use the first equation and find the value of a:</u>

  • 10 = a*2
  • a = 5

<u>The function is:</u>

  • y = 5*2ˣ
4 0
2 years ago
Read 2 more answers
Evaluate c (y + 7 sin(x)) dx + (z2 + 9 cos(y)) dy + x3 dz where c is the curve r(t) = sin(t), cos(t), sin(2t) , 0 ≤ t ≤ 2π. (hin
saw5 [17]
Treat \mathcal C as the boundary of the region \mathcal S, where \mathcal S is the part of the surface z=2xy bounded by \mathcal C. We write

\displaystyle\int_{\mathcal C}(y+7\sin x)\,\mathrm dx+(z^2+9\cos y)\,\mathrm dy+x^3\,\mathrm dz=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r

with \mathbf f=(y+7\sin x,z^2+9\cos y,x^3).

By Stoke's theorem, the line integral is equivalent to the surface integral over \mathcal S of the curl of \mathbf f. We have


\nabla\times\mathbf f=(-2z,-3x^2,-1)

so the line integral is equivalent to

\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\mathrm d\mathbf S
=\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv


where \mathbf s(u,v) is a vector-valued function that parameterizes \mathcal S. In this case, we can take

\mathbf s(u,v)=(u\cos v,u\sin v,2u^2\cos v\sin v)=(u\cos v,u\sin v,u^2\sin2v)

with 0\le u\le1 and 0\le v\le2\pi. Then

\mathrm d\mathbf S=\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv=(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv

and the integral becomes

\displaystyle\iint_{\mathcal S}(-2u^2\sin2v,-3u^2\cos^2v,-1)\cdot(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv
=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=1}u-6u^4\sin^3v-4u^4\cos v\sin2v\,\mathrm du\,\mathrm dv=\pi<span />
4 0
2 years ago
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