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igor_vitrenko [27]
3 years ago
9

What is 893 :9 in long division​

Mathematics
2 answers:
givi [52]3 years ago
4 0
0 remaining 9 i’m just typing more bc it says it’s can’t be under 20 words
erastovalidia [21]3 years ago
3 0
Hi, I’m here to help! Here’s what I got:

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Identify the type of transformation given the rule of V(x, y) = (x,y-1)
irina [24]

Hello!

Given the rule of V(x, y) = (x, y - 1), we can determine that it might be a horizontal or vertical shift.

Since we know that x-values are domain and y-values are range, we know that the range of the function is decreasing by 1 (y - 1), so, the entire function is shifting down one unit.

Therefore, the type of transformation given by the rule is a vertical shift/translation downwards by one unit.

7 0
3 years ago
Find the greatest common factor (GFC) for this pair of composite numbers. 10 and 15
zloy xaker [14]

Given:

The pair of composite numbers: 10 and 15

To find:

The greatest common factor (GFC) for the given pair of composite numbers.

Solution:

Two composite number are 10 and 15.

The factor forms of these two numbers are

10=2\times 5

15=3\times 5

It is clear that the common factor is 5 in both factor forms. So, the greatest common factor is

GCF(10,15)=5

Therefore, the greatest common factor of 10 and 15 is 5.

4 0
3 years ago
Hey can you please help me posted picture of question :)
ladessa [460]
The graph is touching the x-axis at x= 2 and is turning away.

When a graph exhibit such a behavior at a root, we say that the multiplicity of the root is 2. So the roots of the polynomial are x = 2 and x = 2. The factors of the polynomial are (x - 2) and (x - 2)

The polynomial thus can be written as product of its factors as (x-2)(x-2)

So the correct answer to this question is option B
7 0
4 years ago
Expand.<br> Your answer should be a polynomial in standard form.<br> (3c + 2)(c^2-6c-4)
evablogger [386]

Answer:

After expanding the polynomial (3c + 2)(c^2-6c-4) we get  3c^3-16c^2-24c-8

Step-by-step explanation:

We need to expand the polynomial (3c + 2)(c^2-6c-4)

Multiply the terms:

(3c + 2)(c^2-6c-4)\\=3c(c^2-6c-4)+2(c^2-6c-4)\\=3c^3-18c^2-12c+2c^2-12c-8\\=3c^3-18c^2+2c^2-12c-12c-8\\=3c^3-16c^2-24c-8

So, after expanding the polynomial (3c + 2)(c^2-6c-4) we get  3c^3-16c^2-24c-8

3 0
3 years ago
Please help? Graph <img src="https://tex.z-dn.net/?f=-3x%5E2%2B12y%5E2%3D84" id="TexFormula1" title="-3x^2+12y^2=84" alt="-3x^2+
mariarad [96]
-3x^2+12y^2=84
12y^2=3x^2+84
y^2=\dfrac{x^2}4+7
y=\pm\sqrt{\dfrac{x^2}4+7}

For either square root to exist, you require that \dfrac{x^2}4+7\ge0. This is true for all x, since \dfrac{x^2}4 is always non-negative. This means the domain of y as a function of x is all real numbers, or x\in\mathbb R or (-\infty,infty).

Now, because \dfrac{x^2}4+7 is non-negative, and the smallest value it can take on is 7, it follows that the minimum value for the positive square root must be \sqrt7, while the maximum value of the negative root must be -\sqrt7. This means the range is y\in\mathbb R\setminus(-\sqrt7,\sqrt7), or |y|\ge\sqrt7, or (-\infty,-\sqrt7]\cup[\sqrt7,\infty).
6 0
4 years ago
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