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Margarita [4]
2 years ago
6

What are the slopes of these two ?

Mathematics
2 answers:
Veseljchak [2.6K]2 years ago
8 0

Answer:

uh a

Step-by-step explanation:

trasher [3.6K]2 years ago
5 0

Step-by-step explanation:

3)

2x + 3y = 12

Solve for y. Then you have y = mx + b, and m is the slope.

3y = -2x + 12

y = -2/3 x + 12

slope = -2/3

6x - 4y = 8

-4y = -6x + 8

y = -6/(-4) x + 8/(-4)

y = 3/2 x - 2

slope = 3/2

Since the slopes -2/3 and 3/2 are opposite reciprocals, the lines are perpendicular.

4)

3x - 4y = 12

-4y = -3x + 12

y = -3/(-4) x + 12/(-4)

y = 3/4 x - 3

slope = 3/4

4x + 3y = 15

3y = -4x + 15

y = -4/3 x + 5

slope = -4/3

Since the slopes 3/4 and -4/3 are opposite reciprocals, the lines are perpendicular.

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If h= 11 units and r=4 units then what is the approximate volume of the cone
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Write an equation of the perpendicular bisector of the segment with endpoints G 9,8       and H 3,2      .
Norma-Jean [14]

Answer:

y = -x + 11

Step-by-step explanation:

The equation of a straight line is is given by:

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The equation of the line joining G(9, 8) and H(3, 2) is given as:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-8=\frac{2-8}{3-9}(x-9)\\\\y-8=x-9\\\\y=x-1

The perpendicular bisector of the line joining G(9, 8) and H(3, 2) is perpendicular to the line joining G(9, 8) and H(3, 2) and passes through the midpoint of line joining G(9, 8) and H(3, 2).

Let (x, y) be the midpoint of the line joining G(9, 8) and H(3, 2). Hence:

x = (9 + 3)/2 = 6

y = (8 + 2)/2 = 5

The midpoint = (6, 5)

Two lines are perpendicular if the product of their slopes is -1.

The line joining G(9, 8) and H(3, 2) has a slope of 1, hence, the slope of the perpendicular bisector would be -1.

This means that the perpendicular bisector has a slope of -1 and passes through (6, 5). Using:

y-y_1=m(x-x_1)\\\\y-5=-1(x-6)\\\\y-5=-x+6\\\\y=-x+11

The equation of the perpendicular bisector is y = -x + 11

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So you have 6x-30. The only factor I can think of for this is x+5. Because you have 6(x+5)= 6x+30
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