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dsp73
3 years ago
10

Can some PLEASE HELP ME I

Mathematics
1 answer:
erastova [34]3 years ago
6 0

Answer:

B

Step-by-step explanation:

because the equation when you get it is the number you divide with

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What plus what would equal 3744
Murrr4er [49]

1872 + 1872

answers have to be more than 20 characters to post so um..

ELRIS COMEBACK 26/02

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3 years ago
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An oxygen tank contained 212 12/3 liters of oxygen before 27 1/3 liters were used. If the tank can hold 240 3/8 liters, how much
lukranit [14]
So, initially   240\frac{3}{8} -212 \frac{12}{3} were empty:

this is :

240  \frac{3}{8} - 212  \frac{12}{3}  = 240  \frac{3}{8} - 212  +4 = 240  \frac{3}{8} - 216= 24  \frac{3}{8}

12/4 is 4 so that's why i substituted it with 4.

now, later 27 1/3 were used so we add this tho the original empty space

 24  \frac{3}{8}+ 27  \frac{1}{3} =  24  \frac{9}{24}+ 27  \frac{8}{24} = 51  \frac{17}{24}


which is the result!





5 0
3 years ago
Which second-degree polynomial function has a leading coefficient of –1 and root 5 with multiplicity 2?
PIT_PIT [208]
A second degree polynomial function has the general form:

                  \displaystyle{f(x)=ax^2+bx+c, where a\neq0.

The leading coefficient is a, so we have a=-1.

5 is a double root means that :

i) f(5)=0,
ii) the discriminant D is 0, where D=b^2-4ac.

Substituting x=5, we have

                                        f(5)=a(5)^2+b(5)+c,

and since f(5)=0, and a is -1 we have:

                                          0=-25+5b+c
thus c=25-5b.


By ii) \displaystyle{b^2-4ac=0.

Substituting a with -1 and c with 25-5b we have:
                                     
          \displaystyle{b^2-4ac=0
          \displaystyle{b^2-4(-1)(25-5b)=0
          \displaystyle{b^2+4(25-5b)=0
          \displaystyle{b^2-20b+100=0
          \displaystyle{(b-10)^2=0
          \displaystyle{b=10 


Finally we find c: c=25-5b=25-50=-25

Thus the function is        \displaystyle{f(x)=-x^2+10x-25


Remark: It is also possible to solve the problem by considering the form

f(x)=-1(x-5)^2 directly.

In general, if a quadratic function has leading coefficient a, and has a root r of multiplicity 2, then its form is f(x)=a(x-r)^2
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Anna11 [10]
In order to solve, set up a proportion: 22/126=x/100. Cross multiply: 2200=126x. Divide by 126 on both sides: 17.46%=x
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Most likely she incorrectly moved the decimal point in her calculation.  The percent of a group cannot be more than 100.
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