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lesantik [10]
3 years ago
7

A kennel offers day care for dogs twice a week. The box and whisker plots below shows the weights of the dogs that were in day c

are on Tuesday and the dogs that were in day care on Thursday. Which statement about the dogs in day care is most likely true?
Mathematics
1 answer:
Lorico [155]3 years ago
5 0

Answer:

The dogs in a day care on Thursday are more than the dogs on Tuesday.

Step-by-step explanation:

The day care service for dogs is available to the people which helps them perform their routine work while their pets are away. The box and whisker plot given shows that people leave their dogs in the day care more on Thursday rather than on Tuesday.

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Jovani wanted to switch gyms. Fitness 19 charges a one time $39 cleaning fee and $17 per
Alexxx [7]

Answer:

Hi there!

Your answer is:

It will take 2.2 months for both gyms to be the same amount of money!

Step-by-step explanation:

Fitness 19:

39+ 17x

Anytime Fitness:

50+ 12x

Put them equal to each other:

39+17x = 50+12x

-12x

39+5x = 50

-39

5x = 11

/5

x= 2.2 months

39+17(2.2)= 76.4$

50+12(2.2)= 76.4$

Hope this helps!

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3 years ago
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Which statement best describes the expression 3 + y ÷ 2?
Dovator [93]

Answer: Should be "the sum of 3 and the quotient of y and 2"

Step-by-step explanation: pemdas

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Vanyuwa [196]

Answer:

Is this an exam? looks like it

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3 years ago
Suppose that administrators of a large school district wish to estimate the proportion of children in the district enrolling in
11Alexandr11 [23.1K]

Answer:

95% z-confidence interval for the proportion of all children enrolled in kindergarten who attended preschool is between a lower limit of 0.528 and an upper limit of 0.772.

Step-by-step explanation:

Confidence interval = p + or - zsqrt[p(1-p) ÷ n]

p is sample proportion = 39/60 = 0.65

n is the number of children sampled = 60

Confidence level (C) = 95% = 0.95

Significance level = 1 - C = 1 - 0.95 = 0.05

Divide significance level by 2 to obtain critical value (z)

0.05/2 = 0.025 = 2.5%

z at 2.5% significance level = 1.96

zsqrt[p(1-p) ÷ n] = 1.96sqrt[0.65(1-0.65) ÷ 60] = 1.96sqrt[0.2275 ÷ 60] = 1.96sqrt(3.792×10^-3) = 1.96×0.062 = 0.122

Lower limit = p - 0.122 = 0.65 - 0.122 = 0.528

Upper limit = p + 0.122 = 0.65 + 0.122 = 0.772

95% confidence interval is between 0.528 and 0.772

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3 years ago
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