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Fynjy0 [20]
2 years ago
8

Plz help answer all of them

Mathematics
1 answer:
cricket20 [7]2 years ago
3 0
I don’t know the questions because it’s hard I’m
You might be interested in
What is the GCF?<br>6x² + 24x<br>​
Gelneren [198K]

Answer:

6x

6x(x + 4)

Step-by-step explanation:

Both 6x^2 and 24x are divisible by 6x

3 0
3 years ago
WUCLUJ
mash [69]

Answer:

81 degrees

Step-by-step explanation:

A quadrilateral has four interior angles which sum up to 360 degrees.

As we are given that two angles are right angles which means the sum of two angles will be 180 degrees and the third angle is 99 degrees.

As we know that the four angles sum up to 360 degrees.

Let A,B,C and D denote the four angles,

Then

Sum of angles = 360

A+B+C+D=360

90+90+99+D=360

279+D=360

D=360-279

D= 81 degrees

So the fourth angle is 81 degrees ..

7 0
3 years ago
How do you simplify 2/3 divided by 1/3
suter [353]

Answer:

2

Step-by-step explanation:

Solve. To do so, change the division sign into a multiplication sign, and flip the second fraction:

(2/3)/(1/3) = (2/3) x (3/1)

Multiply across:

(2 * 3)/(3 * 1) = (6)/(3)

Simplify:

6/3 = 2

2 is your answer.

~

8 0
3 years ago
*Absurd answers will be reported* Can the fraction 12/30 be reduced/simplified? If it can, what can it be reduced by?
Fynjy0 [20]

Answer:

divided by 3 12/30 = 4/10 = 2/5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. ​(a) Descr
Daniel [21]

Answer:

(a) The sampling distribution of\overline{X} = Population mean = 79

(b)  P ( \overline{X} greater than 81.2 ) =  0.1357

(c) P (\overline{X} less than or equals 74.4 ) = .0107

(d) P (77.6 less than \overline{X} less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean (\nu) = 79

Standard deviation (\sigma ) = 18

​(a) Describe the sampling distribution of \overline{X}

For large sample using central limit theorem

the sampling distribution of\overline{X} = Population mean = 79

​(b) What is Upper P ( \overline{X} greater than 81.2 )​ =

P(\overline{X}> 81.2)  = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})

                    =  P(Z> 1.1)

                    = 1 - P(Z<   1.1)

                    = 1 - .8643 =

                    = 0.1357

(c) What is Upper P (\overline{X} less than or equals 74.4 ) =

P(\overline{X}\leq  74.4) = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq  \frac{74.4- 79}{\frac{18}{\sqrt{81}}})

                    = P(Z\leq  -2.3)

                    = .0107

​(d) What is Upper P (77.6 less than \overline{X} less than 83.2 ) =

P(77.6< \overline{X}<   83.2) = P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq  \frac{83.2- 79}{\frac{18}{\sqrt{81}}})

                                = P(- 0.7< Z<   2.1)

                                 = (Z<   2.1) - (Z<   -0.7)

                                  = 0.9821 - .2420

                                   = 0.7401

3 0
3 years ago
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