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miss Akunina [59]
2 years ago
5

Tom can place 12 eggs per crate.How many eggs must be in 1 crate?

Mathematics
1 answer:
Lisa [10]2 years ago
3 0

1. If he can place 12 eggs in each crate then are 12 eggs in one crate. (12 x 1 = 12)

2. If there are 8 rooms in a house, each with one bed then there are 8 beds in total. (8 x 1 = 8)

3. There are 20 ministers. ( 20 x 1 = 20)

4. If Sam earns $20 per hour, and he works one hour he will earn $20. (20 x 1 = 20)

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How are the semicircle and the diameter of a circle related?
k0ka [10]

Answer:

rThe degree of measure of the simicircle are the same.

Step-by-step explanation:

Im almost positive this is right..

3 0
2 years ago
Read 2 more answers
Nita gana $ 20 por semana paseando al perro de su vecino. También gana $ 2 por cada rosa que vende de su jardín de rosas. Nita q
Rudik [331]

Answer:

La situación está representada por el siguiente sistema:

y = 20+2\cdot x

y \ge 50

Donde:

x - Cantidad de rosas vendidas semanalmente.

y - Ganancia semanal, medida en dólares.

Step-by-step explanation:

De acuerdo con el enunciado, Nita gana una cantidad fija cada semana por pasear al perro de su vecino, con un monto de $ 20, mientras que gana en función de la cantidad de rosas a vender, con un valor unitario de $ 2. Si ella desea ganar al menos $ 50, por tanto, se requiere construir el siguiente sistema, conformado por una ecuación y una inecuación:

y = 20+2\cdot x (1)

y \ge 50 (2)

Donde:

x - Cantidad de rosas vendidas semanalmente.

y - Ganancia semanal, medida en dólares.

4 0
3 years ago
9.4 The heights of a random sample of 50 college stu- dents showed a mean of 174.5 centimeters and a stan- dard deviation of 6.9
gladu [14]

Answer:  a) (176.76,172.24), b) 0.976.

Step-by-step explanation:

Since we have given that

Mean height  = 174.5 cm

Standard deviation = 6.9 cm

n = 50

we need to find the 98% confidence interval.

So, z = 2.326

(a) Construct a 98% confidence interval for the mean height of all college students.

x\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=(174.5\pm 2.326\times \dfrac{6.9}{\sqrt{50}})\\\\=(174.5+2.26,174.5-2.26)\\\\=(176.76,172.24)

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?

Error would be

\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{6.9}{\sqrt{50}}\\\\=0.976

Hence, a) (176.76,172.24), b) 0.976.

8 0
2 years ago
Which of the following is equal to 51/3?
oee [108]
51/3 is equal to 17 hope it helps
7 0
2 years ago
Read 2 more answers
PLS HELP ME ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITs RIGHT OR WRONG.
grin007 [14]

Answer:

It should be 9 m :)

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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