<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of
.
60 out of 100 scores are passing scores, hence 
95% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
A similar problem is given at brainly.com/question/16807970
Answer:
18x+21
Step-by-step explanation:
First multiply each equation by 2 since there is 2 sides for both the length and width.
2(2x+3) 2(7x+9)
4x+3 14x+18
Then combine like terms
4x+14x 3+18
18x 21
Answer:
28.25
Step-by-step explanation:
First, combine like terms.
12y+6=6y+12 turns into
12y-6y=12-6, which is
6y=6. Now divide both sides by 6.
y=1
now do a quick check (cause that's always a good idea).
12(1)+6=6(1)+12
12+6=6+12
18=18 ; )
The product of this equation is 21 when the values of X and Y are imputed into the equation.