A) Variance = 10.24
B) Standard Deviation = 3.2
One of the measurements of dispersion is the standard deviation, which is exclusively used for quantitative data. It aids in determining if the data's mean is a suitable measurement to reflect the core value.
TIME FREQUENCY(f) MIDPOINT(x) d d² fd fd²
0 - 0.9 43 0.45 -3 9 -129 387
1.0 - 1.9 17 1.45 -2 4 -34 68
2.0 - 2.9 19 2.45 -1 1 -19 19
3.0 - 3.9 18 3.45 0 0 0 0
4.0 - 4.9 14 4.45 1 1 14 14
5.0 -5.9 16 5.45 2 4 32 64
∑f = 127
∑fd = -136
∑fd² = 552
Standard Deviation = 
√4.35 - √1.15
Standard Deviation = 3.2
(SD)² = (3.2)² = 10.24
Variance = 10.24
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0.004 is 0.4% in decimal form
Answer:
x=4/3
Step-by-step explanation:
In pic
(hope this helps can I pls have brainlist (crown)☺️)
The domain of the function is [-4, 4) and the range of the function is [-5, 2)
<h3>How to determine the domain and the range of the function?</h3>
<u>The domain</u>
As a general rule, it should be noted that the domain of a function is the set of input values or independent values the function can take.
This means that the domain is the set of x values
From the graph, we have the following intervals on the x-axis
x = -4 (closed circle)
x =4 (open circle)
This means that the domain of the function is [-4, 4)
<u>The range</u>
As a general rule, it should be noted that the range of a function is the set of output values or dependent values the function can produce.
This means that the range is the set of y values
From the graph, we have the following intervals on the y-axis
y = -5 (closed circle)
y = 2 (open circle)
This means that the range of the function is [-5, 2)
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1000 m = 1 km
5000 m = 5 km
They have traveled 5 km so far.
Subtract what they traveled from total distance:
24-5 = 19 km left.
