A zoo has a total of 8 lions and tigers. the number of tigers are one less than twice the number of lions. write a system of equ
1 answer:
<h2>L+T = 8</h2><h2>T = 2L -1</h2>
Step-by-step explanation:
Let the number of lions be represented by L
Let the number of tigers be represented by T
<u>A zoo has a total of 8 lions and tigers</u><u> </u><u>:</u>
<u></u>
<u>Th</u><u>e number of tigers are one less than twice the number of lions.</u><u> </u><u>:</u>
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Complete question:
Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.
A) Find the mean and standard deviation for the number of girls in groups of 36 births.
B) Use the range rule of thumb to find the values separating results that are significantly low and significantly high.
C) Is the result of 33 girls significantly high? A result of 33 girls would suggest the method is effective or is not effective?
Answer:
a) mean = 18
Standard deviation =3
b) low range = 12
High range = 24
c) The result of 33 girls is significantly high. Yes, the method is effective.
Step-by-step explanation:
Given:
p = 0.5
n = 36
a) The mean is the product of n and p
Mean u = np
u = 36 * 0.5 = 18
The standard deviation is the square root of the product of n and p&q.
S.d ó =
b) To find the range rule of thumb:
• For low range
Low range = u - 2ó
= 18 - (2 * 3)
= 12
• High range
= u + 2ó
= 18 + (2*3)
= 24
c) The result is significantly high, because 33 is greater than 24 girls.
A result of 33 girls would prove the method as effective.