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Vsevolod [243]
3 years ago
8

From a population of 500 elements, a sample of 225 elements is selected. It is known that the variance of the population is 900.

The standard error of the mean is approximately
Mathematics
1 answer:
Valentin [98]3 years ago
8 0

Answer:

standard error of the mean (S.E) = 0.06

Step-by-step explanation:

<u><em>Explanation:</em></u>-

Given sample size 'n' = 500

Given variance of the Population = 900

The standard deviation of the Population = √900 = 30

The standard error of the mean is determined by

S.E = \frac{S.D}{\sqrt{n} } = \frac{30}{500} = 0.06

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Which of the following represents the zeros of f(x) = 3x^3 − 10x^2 − 81x + 28?
xxMikexx [17]
Option A). 7, -4 and 1/3

To find the zeros you can factor the polynolial into (3x-1)((x+4)(x-7)

Then:
3x -1 =0 => x = 1/3
x+4=0 => x = -4
x-7 =0 => x =7

Those are the three zeros.

7 0
4 years ago
What should be added to p to get p+q?​
lisov135 [29]

Answer:

Step-by-step explanation:

The correct answer is q

Because we have been given the equation p + q already so if we observe the equation carefully we see that if we add the variable q to the variable p we get the answer p + q

7 0
3 years ago
89 + 217 =<br> 1,564 – 1,438 =<br> 11 X 5 =<br> 72 : 8 =<br> 6 X 10 =<br> 88 + 8 =<br> 4,632-4,608 =
denpristay [2]

Answer:

use a calculator

7 0
3 years ago
Use the parabola tool to graph the quadratic function f(x)=x2−12x+27. Graph the parabola by first plotting its vertex and then p
alina1380 [7]

Answer:

vertex is (6 , -9)

points are (9,0) and (3,0)

Step-by-step explanation:

Given quadratic function f(x)=x^2-12x+27

We have to plot the given quadratic function.

Consider the Given quadratic function f(x)=x^2-12x+27

The general form of quadratic function  is given f(x)=a(x-h)^2+k

Where, (h, k)  is vertex , given  h =\frac{-b}{2a} and k = f(h)  

Thus, for given quadratic function f(x)=x^2-12x+27

a = 1 , b= -12 , c = 27

Thus,

h =\frac{-b}{2a}=\frac{12}{2}=6

k = f(h) that is f(12) = (6)^2 - 12× 6 +27 = 36 - 72 + 27 = - 9

Thus, given  quadratic function f(x)=x^2-12x+27 in standard form is f(x)=(x-6)^2-9  

Thus, vertex is (6 , -9)

For second point put f(x)=0  , we get,

f(x)=(x-6)^2-9=0  

\Rightarrow (x-6)^2-9=0  

\Rightarrow (x-6)^2=9  

\Rightarrow (x-6)=\pm 3  

\Rightarrow x= 6\pm 3  

Thus, \Rightarrow x=6+3=9 and \Rightarrow x=6-3=3  

thus, points are (9,0) and (3,0)

Graph is attached below.

5 0
4 years ago
3x square+6y Square when X=0 and y=2 with steps pls​
Sauron [17]

Answer:

If the equation is 3x^2+6y^2, when x=0 and y=2.

Then, 3(0)^2+6(2)^2=

So, 0+6(4)= 24

Therefore, the answer is 24.

Step-by-step explanation:

8 0
3 years ago
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