In ΔJKL, j = 9.6 inches, k = 6.4 inches and l=8.4 inches. Find the measure of ∠K to the nearest degree.

Need help on precalcues

Vinvika [58]

5 ≥ 2, so the second rule of <em>C(x)</em> applies :

<em>C</em> (5) = 25 + 3•(5 - 2) = 25 + 3•3 = 25 + 9 = 34

7 0

3 years ago

Solve the formula for h. A=bh

Leni [432]

Answer:

A/b = h

Step-by-step explanation:

A=bh

Divide each side by b

A/b=bh/b

A/b = h

3 0

4 years ago

Read 2 more answers

1In a card game, there are 49 cards, 7 of each color of the rainbow (red, orange, yellow, green, blue, indigo,violet). The cards

bogdanovich [222]

Answer:

Step-by-step explanation:

a) No two cards should be of the same colour. So for each of the seven cards we have to choose them from different colours. And for each colour we have 7 cards.

So for the required selection: We first select a card from one particular colour in 7C1 = 7 ways. Then we select the second card for the hand from one of the rest of the colours in 7C1 = 7 ways again as the other colour also has 7 cards. And so on.

So no. of ways in which we have a hand of no two cards to be same = 7 x 7 x 7 x 7 x 7 x 7 x 7 = 7^7 = 8,23,543

b) There are 7 cards numbered 4 each of the 7 rainbow colours. Apart from those we have 42 cards from which we have to choose a hand of 7 thus ensuring that there are no cards numbered 4. So we have to select 7 cards out of 42 which can be done in 42C7 = (42!) / 7!35! = 2,69,78,328

c) There are 3 even numbered cards of each colour:(2,4,6) So a total of 21 even numbered cards and rest 28 odd numbered cards. We can choose 4 even numbered cards out of 21 of them in 21C4 = (21!)/(4!17!) = 5,985 ways

And we can choose 3 odd numbered cards out of 28 of them in 28C3 = (28!)/(3!25!) = 3,276 ways

So number of hands with 4 even and 3 odd numbers = 5985 x 3276 = 1,96,06,860

d) Consider that we have two particular colors of which we want the hand of 7 cards to be made of. For the two colors we get a total of 14 cards. We can select 7 out of these 14 cards in 14C7 = 3,432 ways.

But out of these 3432 ways there are two ways which are not desirable. That is when all seven cards are of either one of the two colors. Because then the criteria that the hand is made of exactly two colors will be violated. Hence we remove those two cases so 3430 ways for any two particular colors.

Now out of the 7 colors we can choose any two in 7C2 = 21 ways

So total number of hands made up of exactly two colors = 21 x 3430 = 72,030

6 0

3 years ago

The Blackburn family has a square field where they keep their cattle. The area of the field is 40,000ft squared, and mr Blackbur

Scilla [17]

Area of a square =a^2
40000=a^2
a=200 inch

Now if u can imagine a square shape with side of 200 inch each.it makes right angles
so use pythagorean theorm

c^2=a^2+b^2
c^2=(200)^2+(200)^2
c=282.84 inch

ength of a fence is 282.84 inch

6 0

4 years ago

In a lottery game, a single ball is drawn at random from a container that contains 25 identical balls numbered from 1 through 25

Solnce55 [7]

Answer:

17/25

Step-by-step explanation:

The equation for the probability of two events that are not mutually exclusive is:

p(A ∨ B) = p(A) + p(B) - p(A ∧ B)

A = the number is prime

B = the number is prime

The numbers are:

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25

Here are the 8 prime numbers that satisfy event A:

3, 5, 7, 11, 13, 17, 19, 23

p(A) = 8/25

Here are the 13 numbers that are greater than 12 that satisfy event B:

13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25

p(B) = 13/25

Here are the 4 numbers that satisfy both event A and event B:

13, 17, 19, 23

p(A ∧ B) = 4/25

p(A ∨ B) = p(A) + p(B) - p(A ∧ B)

p(A ∨ B) = 8/25 + 13/25 - 4/25

p(A ∨ B) = 17/25

7 0

3 years ago