Answer:
A) 1st one
Step-by-step explanation:
because it has a cirlular base and tapers to a point
hope this helps ;)
Multiplying the two pieces of the function together:
![R(x)=500*50 + (-5x)(500) + 125x(50) + 125(-50) \\=25000 -2500x+6250x-625x^2 \\=25000+3750x-625x^2 \\=-625x^2+3750x+25000](https://tex.z-dn.net/?f=R%28x%29%3D500%2A50%20%2B%20%28-5x%29%28500%29%20%2B%20125x%2850%29%20%2B%20125%28-50%29%0A%5C%5C%3D25000%20-2500x%2B6250x-625x%5E2%0A%5C%5C%3D25000%2B3750x-625x%5E2%0A%5C%5C%3D-625x%5E2%2B3750x%2B25000)
. This is a quadratic function, and since the coefficient of <em>x</em>² is negative we know it is opening downward and thus has a maximum. We can find the maximum by finding the vertex. First we find the axis of symmetry:
![x=\frac{-b}{2a} \\ \\=\frac{-3750}{2*(-625)} \\ \\=\frac{-3750}{-1250}=3](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%7D%7B2a%7D%0A%5C%5C%0A%5C%5C%3D%5Cfrac%7B-3750%7D%7B2%2A%28-625%29%7D%0A%5C%5C%0A%5C%5C%3D%5Cfrac%7B-3750%7D%7B-1250%7D%3D3)
. This tell us there will need to be 3 $5 decreases in price, or a $15 decrease, to maximize the function. $50-$15=$35.
We now plug our 3 in for <em>x</em> in our function:
![R(x)=-625-(3^2)+3750(3)+25000 \\=-625(9)+11250+25000 \\=-5625+36250 \\=30,625](https://tex.z-dn.net/?f=R%28x%29%3D-625-%283%5E2%29%2B3750%283%29%2B25000%0A%5C%5C%3D-625%289%29%2B11250%2B25000%0A%5C%5C%3D-5625%2B36250%0A%5C%5C%3D30%2C625)
If they decrease the price their total revenue will be $30,625.
Looking at the function we know that they sell an extra 125 yearbooks for every $5 decrease in price. There were 3 $5 decreases, so 3(125) = 375 extra yearbooks. Add this to the original 500 and we have 375+500=875 yearbooks.
D=daniel
brother=b
d is 3 older than 2 times b
d=3+2b
d=17
subsitute
17=3+2b
subtract 3 from both sides
17-3=3-3+2b
14=0+2b
14=2b
didivde both side by 2
7=b
daniels age in terms of his brother age is
d=3+2b
The correct answer is: 3.29999065 x 10^28
<h2>
Answer: what = 3t </h2>
<h3>
Step-by-step explanation:</h3>
4^t × 2^t = 2^what <em> [convert all terms to the same base (2)]</em>
∴ 2^t × 2^t × 2^t = 2^what <em> [us</em>e the <em>multiplicat law of exponents]</em>
2^(t+t+t) = 2^what <em> [simplify]</em>
2^3t = 2^what
<h3> what = 3t </h3>