Ask question

Ask question

All categories

Vedmedyk [2.9K]

3 years ago

9

3(5)+2(w-1)= Cual es el valor de la expresión algebraica?

1 answer:

nata0808 [166]3 years ago

6 0

Answer:

distribute

2(w-1)

a(b-c)=ab-ac

(3)(5)+(2)(w)+(2)(−1)

=15+2w+−2

combine like terms

15+2w+−2

=(2w)+(15+−2)

=

<h2><em><u>2w+13</u></em></h2>

Step-by-step explanation:

https://qcv.gg/rXpglU

You might be interested in

In an election, about 500,000 people voted in all. What could be the exact number of people who voted in the election?

elixir [45]

I am going to give a few answers:

497,543
504,690
501,991
496,900

6 0

3 years ago

Solve the system of equations using the substitution method. 2x+8y=4 x=−3y+5

goldenfox [79]

Since x=-3y+5, substitute x for -3y+5.

2(-3y+5)+8y=4

Distribute.

-6y+10+8y= 4

2y+10= 4

Subtract 10 on both sides.

2y=-6

Divide by 2.

y=-3

Plug in y=-3.

x=-3(-3)+5
x= 9+5
x=14

(14,-3)

We can check this.

2(14)+8(-3)=4
28-24=4
4=4 <== this works

I hope this helps!
~kaikers

7 0

4 years ago

Plz answer only if u know ur correct

hichkok12 [17]

Answer:

1/2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Delicious77 [7]

Answer:

me too jaja

Step-by-step explanation:

8 0

3 years ago

A credit card company charges 18.6% percent per year interest. Compute the effective annual rate if they compound, (a) annualy,

Darina [25.2K]

Answer:

a) Effective annual rate: 18.6%

b) Effective annual rate: 20.27%

c) Effective annual rate: 20.43%

d) Effective annual rate: 20.44%

Step-by-step explanation:

The effective annual interest rate, if it is not compounded continuously, is given by the formula

$I=C(1+\frac{r}{n})^{nt}-C$

where

<em>C = Amount of the credit granted </em>

<em>r = nominal interest per year </em>

<em>n = compounding frequency </em>

<em>t = the length of time the interest is applied. In this case, 1 year. </em>

In the special case the interest rate is compounded continuously, the interest is given by

$I=Ce^{rt}-C$

(a) Annually

$I=C(1+\frac{0.186}{1})-C=C(1.186)-C=C(1.186-1)=C(0.186)$

The effective annual rate is 18.6%

(b) Monthly

<em>There are 12 months in a year </em>

$I=C(1+\frac{0.186}{12})^{12}-C=C(1.2027)-C=C(0.2027)$

The effective annual rate is 20.27%

(c) Daily

<em>There are 365 days in a year </em>

$I=C(1+\frac{0.186}{365})^{365}-C=C(1.2043)-C=C(0.2043)$

The effective annual rate is 20.43%

(d) Continuously

$I=Ce^{0.186}-C=C(1.2044)-C=C(0.2044)$

The effective annual rate is 20.44%

3 0

3 years ago