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3 years ago

What is the solution of each equation?

Mathematics

1 answer:

Natali5045456 [20]3 years ago

7 0

Answer:

Step-by-step explanation:

2(h-8)-h=h-16

step 1 distribute 2 to whats in the parenthesis

2h-16-h=h-16

step 2 combine like terms

h-16=h-16

add 16 to each side

h=h

subtract h from each side

0=0

this would have an infinite amount of solutions

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How to convert 8.5 hours to hours and minutes

ExtremeBDS [4]

A. 4.25 hrs.....4 25/100 reduces to 4 1/4.......1/4(60) = 60/4 = 15 minutes
so 4.25 hrs = 4 hrs and 15 minutes

b. 8.5 hrs.....8 5/10 reduces to 8 1/2.....1/2(60) = 60/2 = 30 minutes
so 8.5 hrs = 8 hrs and 30 minutes

c. 6.2 hrs.....6 2/10 reduces to 6 1/5.....1/5(60) = 60/5 = 12 minutes
so 6.2 hrs = 6 hrs and 12 minutes

d. 10.8 hrs.....10 8/10 reduces to 10 4/5.....4/5(60) = 240/5 = 48 minutes
so 10.8 hrs = 10 hrs and 48 minutes

8 0

3 years ago

Write a scenario that could work for the following line of best fit: y = 0.2x + 7.6. Explain the slope and intercept in this con

Ipatiy [6.2K]

In this question we know what the “y-intercept is,so if we go to our graph we can easily just plot the point 7.6 on the y axis of a number line. It also gives you the slope in decimal form so we would want to convert that from 0.2 to 1/5. And remember the slope is how many places you move to get to the next point on the number line. So from the point 7.6 we would move up 1 over 5 to the right because it is a positive number. Your line should run across the upper segment of the number line and your line should make a 20 to 30 degree angle shift

4 0

3 years ago

Many elementary school students in a school district currently have ear infections. A random sample of children in two different

Marta_Voda [28]

Answer:

Step-by-step explanation:

The summary of the given data includes;

sample size for the first school $n_1$ = 42

sample size for the second school $n_2$ = 34

so 16 out of 42 i.e $x_1$ = 16 and 18 out of 34 i.e $x_2$ = 18 have ear infection.

the proportion of students with ear infection Is as follows:

$\hat p_1 = \dfrac{16}{42}$ = 0.38095

$\hat p_2 = \dfrac{18}{34}$ = 0.5294

Since this is a two tailed test , the null and the alternative hypothesis can be computed as :

$H_0 :p_1 -p_2 = 0 \\ \\ H_1 : p_1 - p_2 \neq 0$

level of significance ∝ = 0.05,

Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.

The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.

$\bar p = \dfrac{x_1 +x_2}{n_1 +n_2}$

$\bar p = \dfrac{16 +18}{42 +34}$

$\bar p = \dfrac{34}{76}$

$\bar p = 0.447368$

$\bar p + \bar q = 1 \\ \\ \bar q = 1 -\bar p \\ \\\bar q = 1 - 0.447368 \\ \\\bar q = 0.552632$

The pooled standard error can be computed by using the formula:

$S.E = \sqrt{ \dfrac{ \bar p \bar q}{ n_1} + \dfrac{\bar p \bar p}{n_2} }$

$S.E = \sqrt{ \dfrac{ 0.447368 * 0.552632}{ 42} + \dfrac{ 0.447368 * 0.447368}{34} }$

$S.E = \sqrt{ \dfrac{ 0.2472298726}{ 42} + \dfrac{ 0.2001381274}{34} }$

$S.E = \sqrt{ 0.01177284105}$

$S.E = 0.1085$

The test statistics is ;

$z = \dfrac{\hat p_1 - \hat p_2}{S.E}$

$z = \dfrac{0.38095- 0.5294}{0.1085}$

$z = \dfrac{-0.14845}{0.1085}$

z = - 1.368

Decision Rule: Since the test statistics is greater than the rejection region - 1.96 , we fail to reject the null hypothesis.

Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools

5 0

3 years ago

4+8÷2-2×3 what would we do first a 4+8 b8÷2 c2-2 d2×3

murzikaleks [220]

Answer:

multiplication, so d, 2 x 3

Step-by-step explanation:

remember... PEMDAS!!

3 0

2 years ago

I need help please!!

Alex73 [517]

Answer:

Sorry I could only find the answer to the second part.

y=56x

6 0

3 years ago