3 years ago

Help me! i have 20 minutes

Mathematics

1 answer:

KIM [24]3 years ago

5 0

Your on your own.. :/

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For the function f(x)=x2−24÷3+12 f(1) f(0) f(−1)

LuckyWell [14K]

Put the values of x to the equation of the function.

$f(x)=\dfrac{x^2-24}{3}+12$

$f(1)=\dfrac{1^2-24}{3}+12=\dfrac{1-24}{3}+12=\dfrac{-23}{3}+12=-7\dfrac{2}{3}+12=4\dfrac{1}{3}\\\\f(0)=\dfrac{0^2-24}{3}+12=\dfrac{-24}{3}+12=-8+12=4\\\\f(-1)=\dfrac{(-1)^2-24}{3}+12=\dfrac{1-24}{3}+12=\dfrac{-23}{3}+12=-7\dfrac{2}{3}+12=4\dfrac{1}{3}$