Question

I NEED HELP AGAIN PLZ!!!!!

Answer 1

Answer:

cut the polygon into fourths.

since it's a square, the line values of each of the fourth's lines will equate.

find the area of one of the little triangles first.

area of triangle = 1/2 * a * b

area of triangle = 1/2 * 7 * 7 = 24.5

there're 4 triangles.

24.5*4 = 98

98 yds ^ 2

Answer 2

Answer:

The area of your square is 98 yd²

Step-by-step explanation:

The given information about the polygon is half of the diagonal length. Since 7 yds are only half of the diagonal length, we know to add another 7yds to complete the line. Therefore we have 14 as our diagonal length.

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Additional info:

side length a = 9.8994949366117 yd

diagonal q = 14 yd

perimeter P = 39.597979746447 yd

area A = 98 yd²

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Formulas used:

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Area of a square:

A = a2

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Perimeter of a Square

P = 4a

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Polygon diagonals of a square

q = √(2a2) = a√2

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Side of a Square

a = √A

a = P/4

a = q / √2

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I hope I helped, and I always appreciate brainliest!!!   :)