The question is incomplete. Below you will find the missing graph.
The lowest value of the range of the function shown on graph is (B) -2.
Graph is the pictorial representation of the function or mathematical relation.
The lowest value of the graph is the value of y when 
gives the least value.
From the given graph we can clearly see that at 
the graph of the given function approaches the least value which is -2.
So the lowest value of the range of the function shown on the graph is -2.
Hence the correct option is (B).
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Answer:
a = 4
Step-by-step explanation:
a^2 + b^2 = c^2
a= ?
b= 3
c= 5 (c is always the hypotenuse)
*plug in given values
a^2 + 3^2 = 5^2
a^2 + 9 = 25
-9 -9
a^2 = 16
*find the square root
sqrt(a) = sqrt(16)
a = 4
Answer:
B. $36.25+$3.89x≤$58.50
Step-by-step explanation:
It has to be less than or equal to $58.50
The points you are looking for are the midpoints of segments JL and JK.
J(-2, -1), K(4, -5), L(0, -5)
The midpoint of segment JL is
(-2 + 0)/2, (-1 + (-5))/2) = (-2/2, -6/2) = (-1, -3)
The midpoint of segment JK is
(-2 + 4)/2, (-1 + (-5))/2) = (2/2, -6/2) = (1, -3)
Answer: The coordinates are (-1, -3), (1, -3)
