Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
Answer:
I think the answer is 1 7/9
The answer will be C-115.75
You have to times 23 by 5.50 which you will get 126.50
Then you have to subtract that by 10.75
You will get C
Answer:
Step-by-step explanation:
Let
x ---> the number
we know that
The algebraic expression is equal to multiply the number by 4, add 5 and equal 8
so
Solve for x
subtract 5 both sides
Divide by 4 both sides
