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Vanyuwa [196]
3 years ago
10

Explain how solving -7y > 161 is different from solving 7y > -161.

Mathematics
1 answer:
kenny6666 [7]3 years ago
3 0
For the first one you would have to divide -7 to both sides. And for the second one you would have to divide 7. That will isolate the variable and give you the answer for y.
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Need help ASAP! Will give brainliest for decent answer :)
Lena [83]

So sorry I replied so late but I'll leave the answer here just in case.

Answer:

7. Domain: [0,30]  Range: [0,7]

8. f(20) = 4.67 or 4 2/3; After 20 seconds, the squirrel is 4.67 meters away from the camera.

9. x = 1.25 and x = 21.43; The quirrel is 4 meters away from the camera at 1.25 seconds and 21.43 seconds.

10. At 2.5 and 19.29 seconds

11. 10 seconds

12. The squirrel went to the back of the camera, away from its line of view.

Step-by-step explanation:

7. The line is between 0 and 30 on the x-axis and is between 0 and 7 on the y-axis.

8. The slope of the third part of the line is not a whole number, so you need to calculate it. The rise is -7 meters and run is 15 seconds, so the slope is -7/15. Plugin -7/15 into the slope-intercept form (y = mx+b) and the equation is f(x) = -7/15 x+14. Plugin x=20 into the equation:

f(20) = -7/15(20)+14

f(20) = -9.33+14

f(20) = 4.67

9. The first slope of the graph will also need to be calculated. Rise is 7-3 (4) and the run is 5. Slope = rise/run = 4/5 = 0.8. Plugin the slope into y = mx+b with the y-intercept, and the equation is f(x) = 0.8x+3. Replace f(x) with 4 and solve the equation.

4 = 0.8x+3

1 = 0.8x

x = 1.25

There is another x value that matches with f(x) = 4 in the third part of the graph, so we'll use the slope-intercept form for the previous question for this one.

4 = -7/15 x+14

-10 = -7/15 x

x = 21.43

10. The squirel is 5 meters away from the camera twice, so we'll be using the same equations for the previous question.

5 = 0.8x+3

2 = 0.8x

x = 2.5

5 = -7/15 x+14

-9 = -7/15 x

x = 19.29

11. The squirrel is 7 meters away between 5 and 15 seconds. 15-5 = 10.

12. The squirrel most likely went somehwere where the camera can't see it, and it's probably the back of it.

7 0
3 years ago
A radioactive substance decays at a continuous rate of 17% per year, and 250 mg of the substance is present in the year 2009.
yaroslaw [1]

Answer:

a) A(t) = 250 (1-0.17)^t = 250(0.83)^t

b) A(t=14) = 250 (0.83)^{14}= 18.408 mg

c) For this case we want to find when the quantity is below 25 mg, so we can do this:

25 = 250 (0.83)^t

We can divide both sided by 250 and we got:

0.1 = 0.83^t

Now we can apply natural log on both sides and we got:

ln(0.1) = t ln (0.83)

And if we solve for t we got:

t = \frac{ln(0.1)}{ln(0.83)}= 12.358 years

So the answer for this case would be 12.358 years after.

Step-by-step explanation:

Part a

For this case we know that the decay rate per year is about 17% or 0.17 in fraction and the initial amount is 250 mg for 2009, we can define the model like this:

A(t) = A_o (1-r)^t

Where A represent the amount of the substance in mg, r the decay rate = 0.17 and t the number of years after 2009.

Our model for this case would be:

A(t) = 250 (1-0.17)^t = 250(0.83)^t

Part b

For this case we have that t= 2023-2009=14 years, so then we can find the amount of substance like this:

A(t=14) = 250 (0.83)^{14}= 18.408 mg

Part c

For this case we want to find when the quantity is below 25 mg, so we can do this:

25 = 250 (0.83)^t

We can divide both sided by 250 and we got:

0.1 = 0.83^t

Now we can apply natural log on both sides and we got:

ln(0.1) = t ln (0.83)

And if we solve for t we got:

t = \frac{ln(0.1)}{ln(0.83)}= 12.358 years

So the answer for this case would be 12.358 years after.

6 0
3 years ago
0.00000000213 in scientific notation
Pachacha [2.7K]
Hello!
2.13 x <span>10^<span>−<span>9
You want to make sure the number(after you move the decimal places) should be in between 1-10.
2.13 is in between 1-10.
</span></span></span><span><span><span>I hope this helps;)</span></span></span>
4 0
3 years ago
Brainliest and thanks!
VARVARA [1.3K]

Answer:

vertical.

.................

5 0
3 years ago
What would I got if I divide 0 by 0. some people says that the result can be any numbers since
Fynjy0 [20]

Answer:

you'd get 0 because anything multiplied or divided by 0 is 0

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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