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katrin2010 [14]
3 years ago
15

Stephanie, Mike , and Howard gather blackberries for their grandmother. Stephanie picks 4 3/8 pounds, Mike picks 2.5 pounds, and

Howard gathers 3 1/4 pounds of blackberries. If they place all the blackberries in one bowl and divide the amount equally, how may pounds will each person give to their grandmother?
A 3.0412 pounds

B 3.0 pounds

C 3.375 punds

D 3 1/3 punds​
Mathematics
2 answers:
Zarrin [17]3 years ago
8 0

Answer:B

Step-by-step explanation:

I don’t know

raketka [301]3 years ago
7 0

Answer:

C 3.375 pounds

Step-by-step explanation:

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What is 9 3/4 as a percent
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Given an investment of $2300, after 7 months, earning 6.6% APR, compounded monthly, the future value is given by
AVprozaik [17]

we are given

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What would be the value of expressing something like the national debt in scientific notation? What information would be lost in
Vikki [24]
<span>As of January 8, 2015, the U.S. is $18.1 trillion in debt. (Source: National Priorities Project)

1 Trillion 

= 1 Thousand Billion

= 1,000,000,000,000

= 10</span>¹²
<span>
---------------------------

U.S National debt currently stands at:

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</span><span>
*What information would be lost? Well firstly the 0's. The 0's put the size of the number into perspective. The word "trillion" would also be taken out of the picture, once again altering the perspective of the number.

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8 0
3 years ago
Carisoprodol, a generic muscle relaxer, claims to have, on average, at least 120 milligrams of active ingredient. An independent
katovenus [111]

Answer:

The approximate p-value for the suitable test

<em>0.05 < p < 0.1</em>

|t| = |-1.5806| = 1.5806

t = 1.5806 < 2.009 at 0.05 level of significance

<em>Carisoprodol, a generic muscle relaxer, claims to have, on average, is equal to 120 milligrams of active ingredient.</em>

<u>Step-by-step explanation</u>:

<u><em>Step(i)</em></u>:-

Given mean of the Population 'μ' = 120 milligrams

Given random sample size  'n' = 50

Given mean of the sample x⁻ = 116.2 milligrams

Standard deviation of the sample 'S' = 17 milligrams

Null hypothesis :  'μ' = 120

Alternative hypothesis : 'μ' < 120

<u><em>Step(ii):</em></u>-

<em>Test statistic </em>

t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }

t = \frac{116.2 - 120}{\frac{17}{\sqrt{50} } } = \frac{-3.8}{2.404} = -1.5806

<em>Degrees of freedom</em>

<em>ν = n-1 = 50 -1 =49</em>

t₀.₀₅ = 2.009

|t| = |-1.5806| = 1.5806

t = 1.5806 < 2.009 at 0.05 level of significance

<em>Null hypothesis is accepted</em>

<em>Carisoprodol, a generic muscle relaxer, claims to have, on average, is equal to 120 milligrams of active ingredient.</em>

<u><em>P- value:-</em></u>

<em>The test statistic |t| = 1.5806 at 49 degrees of freedom</em>

<em>The test statistic value is lies between 0.05 to 0.1</em>

<em>0.05 < p < 0.1</em>

<u><em></em></u>

3 0
3 years ago
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