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Alecsey [184]
3 years ago
9

An analogue sensor has a bandwidth which extends from very low frequencies up to a maximum of 14.5 kHz. Using the Sampling Theor

em, what is the minimum sampling rate (number of samples per second) required to convert the sensor signal into a digital representation?
If each sample is now quantised into 2048 levels, what will be the resulting transmitted bitrate in kbps?

Give your answer in scientific notation to 1 decimal place.

Hint: you firstly need to determine the number of bits per sample that produces 2048 quantisation levels
Computers and Technology
2 answers:
spin [16.1K]3 years ago
6 0

Answer:

Sorry didn't mean to click answer, and now not sure how to delete

Explanation:

shepuryov [24]3 years ago
3 0

Answer:

3.2*10^5

Explanation:

By Nyquist's theorem we must have 2*14.5kHz=29kHz so 29,000 samples per second. 2048=2^11 so we have 11 bits per sample. Finally we have 29000*11 bits per second (bps) =319000=3.2 * 10^5

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tatiyna

Answer:

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Explanation:

ifstream objects maintain a filebuf object as their internal stream buffer, and perform operations like input/output on the available associated files.

In above statements.

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Answer:

In Python:

N = int(input("Positive integer: "))

if N > 0:

   flag = False

   for i in range(1,N+1):

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Explanation:

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If the number is positive

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The loop is exited

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   print(str(flag))

If otherwise, that the number is not positive

<em>else:</em>

<em>    print("Positive integer only")</em>

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