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Vladimir [108]
3 years ago
12

Which ordered pair is a solution of the equation y = 10x?​

Mathematics
1 answer:
ddd [48]3 years ago
6 0

Answer:

THE ANSWER WILL BE...

NOTE : Just substitute the x and y variable with (-6,-60) and you will see I am right.

Example:

-60= 10(-6)

<em><u>Please mark as brainliest</u></em>

Have a great day, be safe and healthy

Thank u  

XD

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Find the equation of the line contains the given points p1(-4,-8) p2(-1,-5)
yawa3891 [41]
Ok use the equation for slope which is rise over run and then plug into the equation y= mx+b and solve for b and then use in the equation
7 0
3 years ago
IM GIVING BRAINLIEST!!<br> What two integers between -100 and -20 could be divided to equal 0?
kari74 [83]

Answer:

0

Step-by-step explanation:

What divided by what equals 0? What divided by what equals 0? Specifically, what positive whole number (X) can you divide by another positive whole number (Y) to get 0? The answer is infinite.

4 0
3 years ago
6x - 8y - 5x + 3y so please tell me the answer.<br> thanks
Sonbull [250]

Answer:

x - 5y

Step-by-step explanation:

Let's solve your question together,

6x - 8y - 5x + 3y

first arrange them according to their variable.

6x - 5x - 8y + 3y

Now, solve

x - 5y

Hope this helps :)

6 0
3 years ago
Today, you deposit $2,400 in a bank account that pays 4 percent simple interest. how much interest will you earn over the next 5
Leviafan [203]
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interest rate, i = 4% (=0.04)
number of years, n=4

Simple interest,
I = Pin
=2400*0.04*4
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5 0
3 years ago
A guy wire is attached to the top of a radio antenna and to a point on horizontal ground that 40 m from the base of the antenna.
frutty [35]

Answer:

The length of the wire is 76.19 m.

Step-by-step explanation:

It is given that a guy wire is attached to the top of a radio antenna and to a point on horizontal ground that 40 m from the base of the antenna.

It means base of the right angled triangle is 40 m.

The wire makes an angle of 58deg 20min with the ground.

1 degree = 60 min

Using this conversion convert the given angle in degree.

58^{\circ}20'=58^{\circ}\frac{20}{60}^{\circ}=58\frac{1}{3}^{\circ}=\frac{175}{3}^{\circ}

In a right angled triangle

\cos \theta=\frac{adjacent}{hypotenuse}

\cos (\frac{175}{3}^{\circ})=\frac{40}{hypotenuse}

0.525=\frac{40}{hypotenuse}

hypotenuse=\frac{40}{0.525}

hypotenuse=76.190

Therefore the length of the wire is 76.19 m.

3 0
3 years ago
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