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GalinKa [24]
2 years ago
5

You are ordering shirts for the math club at your school. Short-sleeved shirts cost $10 each. Long-sleeved shirts cost $12 each.

You have a budget of $300 for the shirts. Let x = the number of short sleeved shirts and let y = the number of long sleeve shirts.
Twelve students decide they want short-sleeved shirts. How many long-sleeved shirts can you order?
Mathematics
1 answer:
disa [49]2 years ago
3 0

Answer:

15 long-sleeved shirts can be ordered.

Step-by-step explanation:

x = amount of short-sleeved.

y = amount of long-sleeved.

10x + 12y = 300

10(12) + 12y = 300

120 + 12y = 300

12y = 300 - 120

12y = 180

y = 180 / 12

y = 15

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Answer:19

Step-by-step explanation:

90 - 23 = 67, 67 = 4x - 9, 76 = 4x, 76 / 4 = 19

8 0
3 years ago
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Ann [662]

Answer:

We will split the trapezoid into right angle triangle and rectangle

Traingle with base 3cm and height 10 - 6 = 4cm

Area of traingle

       = \frac{1}{2}*base *height = \frac{1}{2} * 3 * 4 = 6cm^{2}

Area of rectangle with sides 6cm and 3cm

       =6 * 3 = 18cm^{2}

Therefore, area of the trapezoid

       = 6+18 = 24cm^{2}

Area of the semi circle with radius 3/2 = 1.5cm

        = \frac{1}{2}\pi r^{2}  = \frac{1*\pi *1.5*1.5}{2} = 1.125\pi cm^{2}

Total area = 24 + 1.125\pi =27.53cm^{2}

8 0
3 years ago
Of all the species in the world, 3 out of every 5 are insects. What percentage of species are insects?
Anni [7]

Answer:

perhaps 60%?

Step-by-step explanation:

3 0
3 years ago
What is the value of y if 13/9 = y/18
Maslowich

Answer:

y=26

Step-by-step explanation:

1. Swap sides

\frac{13}{9}=\frac{y}{18}

Swap sides:

\frac{y}{18}=\frac{13}{9}

2. Isolate the y

\frac{y}{18}=\frac{13}{9}

Multiply to both sides by 18:

\frac{y}{18}\cdot 18=\frac{13}{9}\cdot 18

Group like terms:

\frac{1}{18}\cdot 18y=\frac{13}{9}\cdot 18

Simplify the fraction:

y=\frac{13}{9}\cdot 18

Multiply the fractions:

y=\frac{13\cdot 18}{9}

Simplify the arithmetic:

y=26

---------------------------

Why learn this:

  • Linear equations cannot tell you the future, but they can give you a good idea of what to expect so you can plan ahead. How long will it take you to fill your swimming pool? How much money will you earn during summer break? What are the quantities you need for your favorite recipe to make enough for all your friends?
  • Linear equations explain some of the relationships between what we know and what we want to know and can help us solve a wide range of problems we might encounter in our everyday lives.

---------------------

Terms and topics

  • Linear equations with one unknown

The main application of linear equations is solving problems in which an unknown variable, usually (but not always) x, is dependent on a known constant.

We solve linear equations by isolating the unknown variable on one side of the equation and simplifying the rest of the equation. When simplifying, anything that is done to one side of the equation must also be done to the other.

An equation of:

ax+b=0

in which a and b are the constants and  x is the unknown variable, is a typical linear equation with one unknown. To solve for x in this example, we would first isolate it by subtracting b from both sides of the equation. We would then divide both sides of the equation by a resulting in an answer of:

x = -b/a

8 0
2 years ago
A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in
Oksi-84 [34.3K]

Answer: The concentration of X is 7.13582\times 10^{-6} and the concentration of Y is 2.53159\times 10^{-5}.

Step-by-step explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

                               Compound X             Compound Y

272                               16400                            3870

327                                3990                             6420

So, our equations becomes

16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191

By solving these two equations, we get that

C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}

Hence, the concentration of X is 7.13582\times 10^{-6} and the concentration of Y is 2.53159\times 10^{-5}.

5 0
3 years ago
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