We need to determine the radius and diameter of the circle. If the area of the circle is 10 pi in^2, then, according to the formula for the area of a circle,
A = 10 pi in^2 = pi*r^2. Thus, 10 in^2 = r^2, and r = radius of circle = sqrt(10) in.
Thus, the diam. of the circle is 2sqrt(10) in. This diam. has the same length as does the hypotenuse of one of the triangles making up the square.
Thus, [ 2*sqrt(10) ]^2 = x^2 + x^2, where x represents the length of one side of the square. So, 4(10) in^2 = 2x^2. Then:
40 in^2 = 2x^2, or 20 in^2 = x^2, and so the length x of one side of the square is sqrt(20). The area of the square is the square of this result:
Area of the square = x^2 = [ sqrt(20) ]^2 = 20 in^2 (answer). Compare that to the 10 pi sq in area of the circle (31.42 in^2).
D = rt
/r /r
D/r = T
*sample text*
Answer/Step-by-step explanation:
Total Distance = 3Ft
a) Determine the amplitude and period of a sinusoidal function that models the bobbing buoy.
Amplitude = 3/2 = 1.5 period = 10 second
No ph. Shift
b) Write an equation of a function that models the buoy with x=0 at its highest point.
y= 1.5 cos ( 
)
Answer:
Step-by-step explanation:
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