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3 years ago

Which of the following controls what enters or exits a cell?

Mathematics

1 answer:

zzz [600]3 years ago

7 0

Answer:

The cell membrane

Step-by-step explanation:

The function of the cell membrane is to regulate what forgien substances come in and out of the cell.

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Cuál es el capital final de invertir $65.000 durante 5 años a una tasa de interés simple del 5% anual? * 1 punto

SashulF [63]

Respuesta:

$81.250.

Explicación paso a paso:

Datos dados

Principal = $ 65,000

Tasa = 5%

Tiempo = 5 años

La expresión de interés simple se da como

A = P (1 + rt)

Substiute

A = 65000 (1 + 0,05 * 5)

A = 65000 (1 + 0,25)

A = 65000 (1,25)

A = $ 81,250

Por lo tanto, la inversión después de 5 años es de $81,250

6 0

3 years ago

What would (10x^2+8xy-20)-(2x^2+3xy+5) equal??

SSSSS [86.1K]

5 0

3 years ago

. Tommy gives baseball cards to four of his friends. He gives Kiana 3 cards less than he gives Gary.

Licemer1 [7]

We need to write system of equations for this problem. Reading text we write 1 equation by 1.
first lets name our variables
x - Kiana cards
y - Gary cards
z - Monty cards
m - Willa cards

x = y-3 which we can write as y = x+3
z = x + 7
m = 2z
x + y + z + m = 74

I think easiest way to solve this is to express all variables in last equation and solve for x.
x + x+3 + x + 7+ 2x + 14= 74
5x = 50
x = 10
now we just calculate cards given to each friend

y = 13
z = 17
m = 34

7 0

3 years ago

What is the volume of a cylinder with a height of 15 and a radius of 11 ???????????????

DiKsa [7]

Volume of a Cylinder = πr²h
V = π * (11)² * 15
v = π * 121 * 15
v = 1815π units³

In short, Your Answer would be Option C

Hope this helps!

7 0

3 years ago

A rectangular lamina of uniform density is situated with opposite corners at (0,0) and (15,4). calculate its radii of gyration a

Sphinxa [80]

First, you have to find the moment of inertia along the x and y axes. Constant density is denoted as k.

$I_{x}= \int\limits^15_0\int\limits^4_0 {k y^{2} } \, dx dy= \frac{1}{3}k (15-4)^4=4880.33k$

$I_{y}= \int\limits^15_0\int\limits^4_0 {k x^{2} } \, dx dy= \frac{1}{3}k (15-4)^4=4880.33k$

Then, the radii of gyration for

x = √[I_x/m]
y = [I_y/m]

where m = k(15-4)² = 121k. Then,

x = y = [4880.33k/121k] = 40.33

I hope I was able to help you. Have a good day.

7 0

3 years ago