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Kipish [7]
3 years ago
15

What is the GCF of 81 and 180?

Mathematics
1 answer:
IgorC [24]3 years ago
4 0

Answer:

9

Step-by-step explanation:

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What is the solution to 9+4n -79
Vlada [557]

Answer:

17.5

Step-by-step explanation:

You have to find n right?

9+4n-79 = 0

-> 4n = 70

-> n = 17.5

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2 years ago
3. Let sin 21 = 0.358. What is the value of x for cos x=0.358?
r-ruslan [8.4K]

Answer:

\cos(69)

Step-by-step explanation:

We will use the co-function identity for sine, where:

\sin(x)=\cos(90-x)

Since sin(21)=0.358=cos(x). This means that:

21=90-x

Solve for x. Add x to both sides:

x+21=90

Subtract 21 from both sides:

x=69\textdegree

Hence:

\sin(21)=\cos(69)\approx0.358

6 0
3 years ago
Need help simplifying this
diamong [38]

The simplified answer is \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}.

<u>Step-by-step explanation:</u>

$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term (\frac{3x+y}{3x+y}) and 2nd term by (\frac{z+2x}{z+2x})

= \frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= \frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}

Now, the denominators are same, you can subtract it.

= \frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

= \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

Thus the simplified solution is  \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

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3 years ago
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If you're talking about the soccerball to football one, it would be a
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