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3 years ago

Are the two triangles congruent ? Please answer correctly !!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!

Mathematics

2 answers:

mel-nik [20]3 years ago

4 0

Answer:

yes

Step-by-step explanation:

MrMuchimi3 years ago

3 0

Answer:

Step-by-step explanation:

None of the given sides or angles are congruent, so they are not congruent.

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Calculate the length of the circumference of a circle with a diameter of 4cm

MakcuM [25]

Length of circumference is 2πr
2 π r and r is equal to 2 cm
I.e 12.5 cm

6 0

3 years ago

What is the equation of a line with a slope of 4 and a y-intercept of 2?

Trava [24]

Answer:

y=4x+2 or f(x)=4x+2

Step-by-step explanation:

This is because the equation format for a line is y=mx+b, the slope is m and the y-intercept is b. So all you have to do is fill it out to get y=4x+2. Or the other way I listed the equation is right too. Hope this helps!

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3 years ago

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Decide if you would use the mean or median for the best measure of central tendency of real estate prices below from a neighborh

never [62]

Answer:

$855,000

Step-by-step explanation:

$855,000 it's alot of money.

I helped you a lot... I'm sure you will pass

4 0

3 years ago

(x^2 - x^(1/2))/(1-x^(1/2))

Levart [38]

$\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 } } \right) }{ \left( 1-{ x }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot 1$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot \frac { \left( 1+\sqrt { x } \right) }{ \left( 1+\sqrt { x } \right) }$

$\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }$

$\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\} }{ \left( 1-x \right) }$

$\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }\left( 1+{ x }^{ \frac { 2 }{ 2 } } \right) -x$

$\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }-{ x }^{ \frac { 3 }{ 2 } }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x$

3 0

3 years ago

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Need help asap

vlabodo [156]

Answer:

7680

Step-by-step explanation:

16(24)20

7680

8 0

3 years ago

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