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sergij07 [2.7K]
3 years ago
6

What is the measure of ZA?

Mathematics
1 answer:
ehidna [41]3 years ago
8 0
B. 60°
This is an equilateral triangle, so all angles should be equal. 180/3=60, so you’re answer is 60.
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point b (3,6) is dilated from the origin by a scale factor of r = 2/3 . what are the coordinates of b’
frez [133]

joke 1. 2 hunters were out in the woods right while they were following fresh tracks from a big elk one of the hunters drop to the ground and his eyes roll backwards so the other hunter whips out his phone and calls the hospital "I THINK MY FRIEND IS DEAD!" he told the doctor the doctor told him " Calm down let's make sure he's dead. so there is a moment of silence the you here a big pop the hunter says "NOW WHAT!"     (he shot his friend)

joke 2. I wanted to be a democrat for halloween but i could not stick my head far enough up my a/s/s to be one.

Joke 3. What has more lives than a cat?  A frog cause it croaks every night.

brainliest for being funny?

3 0
3 years ago
2) 83,97,85,84,96, 80,80,87,91<br> Mean median and mode
marusya05 [52]

\text {Hi! Let's Solve this Problem!}

\text {Before you find the Mean, Medina and Mode you must put the numbers in order.}

\text {Before: 83, 97, 85, 84, 96, 80, 80, 87, 91}\\\text {After: 80, 80, 83, 84, 85, 87, 91, 96, 97}

\underline {\text {Mean}}

\text {To Find the Mean you must Add all the Numbers then Divide.}

\text {Add:} \text 80+80+83+84+85+87+91+96+97=\fbox {783}}

\text {Divide:} \text {783/9=}

\text {The Mean Is:}

\fbox {87}

\underline {\text Median}}

\text {To find the Median you find the number that's in the middle of the set.}

\text {Put your Left Pointer Finger on 83. Put your Right Pointer Finger on 91.}

\text {Move your Left Finger to the Right. Move your Right Finger to the Left.}

\text {Once your Left Finger makes it to 84 and your Right Finger makes it to 87} \text {it shows that 85 is left in the middle.}

\text {The Median Is:}

\fbox {85}

\underline {\text {Mode}}

\text {Finding the Mode means finding the number} \text { that shows the most in the number set given.}

\text {Since 80 is the number that is showing more than any other number} \text {this tells us that 80 is our Mode.}

\text {The Mode Is:}

\fbox {80}

\text {Best of Luck!}

4 0
4 years ago
Please help? Thanks if you do cause I really need it :))
krek1111 [17]
The last two would be your answer :)
7 0
3 years ago
Justify each step. <br> 3•(10•12)=3•(12•10)<br> =(3•12)•10<br> =36•10<br> =360
ziro4ka [17]

Answer:

3•(10•12)=3•(12•10) = 360 = True

Step-by-step explanation:

left-hand side Simplify the following:

3×10×12

10×12 = 120:

3×120

3×120 = 360:

Answer: 360

______________________

Right-hand side:

Simplify the following:

3×12×10

Hint: | Multiply 12 and 10 together.

12×10 = 120:

3×120

Hint: | Multiply 3 and 120 together.

3×120 = 360:

Answer: 360

5 0
3 years ago
Evaluate the integral by changing to polar coordinatesye^x dA, where R is in the first quadrant enclosed by the circle x^2+y^2=2
34kurt
\displaystyle\iint_Rye^x\,\mathrm dA=\int_{\theta=0}^{\theta=\pi/2}\int_{r=0}^{r=5}r^2\sin\theta e^{r\cos\theta}\,\mathrm dr\,\mathrm d\theta

which follows from the usual change of coordinates via

\begin{cases}\mathbf x(r,\theta)=r\cos\theta\\\mathbf y(r,\theta)=r\sin\theta\end{cases}

and Jacobian determinant

|\det J|=\left|\begin{vmatrix}\mathbf x_r&\mathbf x_\theta\\\mathbf y_r&\mathbf y_\theta\end{vmatrix}\right|=|r|

Swap the order, so that the integral is

\displaystyle\int_{r=0}^{r=5}\int_{\theta=0}^{\theta=\pi/2}r^2\sin\theta e^{r\cos\theta}\,\mathrm d\theta\,\mathrm dr

and now let \sigma=r\cos\theta, so that \mathrm d\sigma=-r\sin\theta. Now, you have

\displaystyle\int_{r=0}^{r=5}\int_{\sigma=0}^{\sigma=r}re^\sigma\,\mathrm d\sigma\,\mathrm dr=\int_{r=0}^{r=5}r(e^r-1)\,\mathrm dr=4e^5-\dfrac{23}2
7 0
3 years ago
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