Answer:
The number of minutes of the ride that are spent higher than 15 meters above the ground is 18 minutes.
Step-by-step explanation:
We will use the sin function for the height of the Ferris wheel.
A = amplitude
C = phase shift
D = Vertical shift
2π/B = period
From the provided information:
A = 15/2 = 7.5 m
Compute the Vertical shift as follows:
D = A + Distance of wheel from ground
= 7.5 + 1
= 8.5
The equation of height is:
Now at <em>t</em> = 0 the height is, h (t) = 1 m.
Compute the value of <em>C</em> as follows:
So, the complete equation of height is:
Compute the number of minutes of the ride that are spent higher than 15 meters above the ground as follows:
h (t) ≥ 15
Thus, the number of minutes of the ride that are spent higher than 15 meters above the ground is 18 minutes.
The distance of the ship from the point of the origin can be determined through the trigonometric functions derived from the given distances and the angle.
If we are to draw the ship with the distances traveled in the Cartesian plane, the abscissa (x-coordinate) and the ordinate (y-coordinate) can be determined as follow:
In the second part of the journey, the angle between the x-axis and the ship should be 90-25° = 65°
x-coordinate = y(cos 65°) = 0.4226y
2nd part of y-coordinate = y(sin 65°) = 0.906y
The first part of the y-coordinate is given to be x.
Thus, the expression that can be used to determine the ship's distance from the original point is,
<em> d = sqrt ((0.4226y)² + (x+0.906y)²)</em>
Answer:
Do the ratios 9/10 and 2/4 form a proportion?anation:
Step-by-step expl
Check the picture below.
first off let's check what "h" is in the triangular face.
so, the gazebo has 4 squarish faces, each 12x12, recall 48 ÷ 4 = 12, and it has 4 triangular faces, each with a height of 8 and a base of 12.
notice we're skipping the top and bottom of the cube and the bottom of the pyramid because they're not part of the "surface area".
Can't see what it is about