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3 years ago

5

Which of the following equations represents a line that is

2 answers:

tester [92]3 years ago

6 0

Answer:

cfc

Step-by-step explanation:

cfc

natima [27]3 years ago

6 0

Answer:

3

Step-by-step explanation:

you suck

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What is the value of 6 + 2x2, when x = 3?<br> X

Lyrx [107]

6 + 2(x)2
6 + 2(3)2
=6 + 6(2)
=6 + 12
=18

5 0

3 years ago

Read 2 more answers

Feliz [49]

Answer:

<h2>: 7-⁴</h2>

Step-by-step explanation:

<h3>Exponential Form :</h3><h3>(a^m*a^n ) = (a^m+n )</h3>

<h3>7^-6 = 7^-2 * x </h3>

<h3>(only 7^-4 the term that can add to 7^-2 gives </h3><h3>= 7^-6 )</h3>

<h3>7^-6 = 7^-2 + 7^-4 </h3>

<h3> ( a^m*a^n) = ( a^m+n)</h3>

6 0

3 years ago

One angle is 25 less than four times it's supplement. What is the measure of both angles?

Elenna [48]

Let the first angle be x and the second be y.

Supplementary angles add up to 180, so:
x + y = 180

Also, as given in the statement:
x = 4y - 25

Substituting into the first equation:
4y - 25 + y = 180
5y = 205
y = 41

x = 4(41) - 25
x = 139

One angle is 139° and the other is 41°.

6 0

3 years ago

Find the equation of the line perpendicular to y =<br> 3x + 6 and containing the point (-9,-5).

neonofarm [45]

The equation of the line perpendicular to y = 3x + 6 and containing the point (-9,-5) is $y = \frac{-1}{3}x - 8$

<em><u>Solution:</u></em>

Given that line perpendicular to y = 3x + 6 and containing the point (-9, -5)

We have to find the equation of line

<em><u>The slope intercept form is given as:</u></em>

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

<em><u>Let us first find the slope of line</u></em>

The given equation of line is y = 3x + 6

On comparing the given equation of line y = 3x + 6 with eqn 1, we get,

m = 3

Thus the slope of given equation of line is 3

We know that <em>product of slopes of given line and slope of line perpendicular to given line is equal to -1</em>

Slope of given line $\times$ slope of line perpendicular to given line = -1

$3 \times \text{ slope of line perpendicular to given line }= -1$

$\text{ slope of line perpendicular to given line } = \frac{-1}{3}$

Let us now find the equation of line with slope $m = \frac{-1}{3}$ and containing the point (-9, -5)

Substitute $m = \frac{-1}{3}$ and (x, y) = (-9, -5) in eqn 1

$-5 = \frac{-1}{3}(-9) + c\\\\-5 = 3 + c\\\\c = -8$

<em><u>Thus the required equation of line is:</u></em>

Substitute $m = \frac{-1}{3}$ and c = -8 in eqn 1

$y = \frac{-1}{3}x - 8$

Thus the required equation of line perpendicular to given line is found

6 0

4 years ago

The question is in the picture <br> PLEASE HURRY!!!!

dsp73

Answer:

1, 3, 5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers