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NeTakaya
2 years ago
5

Please see question below.

Mathematics
2 answers:
Likurg_2 [28]2 years ago
6 0

Answer:

112% of 50 is 56

Step-by-step explanation:

100% of 50 is 50.

We have to find 12% of 50, and then add it to 50 to get 112% of 50.

12% of 50 is the same as .12 x 50 which is 6.

50 + 6 = 56

I Hope That This Helps! :)

Papessa [141]2 years ago
4 0

Answer: 56

Step-by-step explanation:

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Apply the zero product property to solve the equation below:<br> x (x + 2) = 0
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Answer:

0(-2+2)=0

Step-by-step explanation:

x=0

x=-2

0(-2+2)=0

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Step-by-step explanation:

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The temperature will decrease by 7.5 F
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2 years ago
3. Complete the proof below.<br><br><br> Help please!!!
baherus [9]

Answer:

The completed proof is presented as follows;

The two column proof is presented as follows;

Statements    {}                                               Reason

1. \overline {HI} ║ \overline {KL}, J is the midpoint of \overline {HL} {}         1. Given

2. ∠IHJ ≅ ∠JLK{}                                            2. Alternate angles are congruent

3. ∠IJH ≅ ∠KJL   {}                                         3. Vertically opposite angles

4.  \overline {HJ} ≅ \overline {JL}   {}                                              4. Definition of midpoint

5. ΔHIJ ≅ ΔLKJ  {}                                         5. By ASA rule of congruency

Step-by-step explanation:

Alternate angles formed by the crossing of the two parallel lines \overline {HI} and \overline {KL}, by the transversal \overline {HL} are equal

Vertically opposite angles formed by the crossing of two straight lines \overline {IK} and \overline {HL} are always equal

A midpoint divides a line into two equal halves

Angle-Side-Angle, ASA rule of congruency states that two triangles ΔHIJ and ΔLKJ, that have two congruent angles, ∠IHJ in ΔHIJ ≅ ∠JLK{} in ΔLKJ and ∠IJH in ΔHIJ ≅ ∠KJL in ΔLKJ, and that the included sides between the two congruent angles is also congruent \overline {HJ} ≅ \overline {JL}, then the two triangles are congruent, ΔHIJ ≅ ΔLKJ.

5 0
2 years ago
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