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denis-greek [22]

3 years ago

9

Please I need some serious help with this.. Thank you

1 answer:

vfiekz [6]3 years ago

6 0

Answer:

the pdf your showing is not showing for me its just blank ???!

Step-by-step explanation:

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Help help please answer this question and no link

arsen [322]

I hope this helps! May you have a great day today! ❤️

8 0

4 years ago

The value of an investment A (in dollars) after t years is given by the function A(t) = A0ekt. If it takes 10 years for an inves

Ludmilka [50]

Answer:

20 years.

Step-by-step explanation:

We have been given a formula $A(t)=A_0\cdot e^{kt}$ , which represents the value of an investment A (in dollars) after t years.

Substitute the given values:

$\$3,000=\$1,000\cdot e^{k*10}$

Let us solve for k.

$\frac{\$3,000}{\$1,000}=\frac{\$1,000\cdot e^{k*10}}{\$1,000}$

$3=e^{k*10}$

Take natural log of both sides:

$\text{ln}(3)=\text{ln}(e^{k*10})$

Using property $\text{ln}(a^b)=b\cdot \text{ln}(a)$ , we will get:

$\text{ln}(3)=10k\cdot\text{ln}(e)$

We know that $\text{ln}(e)=1$ , so

$\text{ln}(3)=10k\cdot 1$

$\text{ln}(3)=10k$

$\frac{\text{ln}(3)}{10}=\frac{10k}{10}$

$\frac{\text{ln}(3)}{10}=k$

$\$9,000=\$1,000\cdot e^{\frac{\text{ln}(3)}{10}*t}$

Dividing both sides by 1000, we will get:

$9=e^{\frac{\text{ln}(3)}{10}*t}$

Take natural log of both sides:

$\text{ln}(9)=\text{ln}(e^{\frac{\text{ln}(3)}{10}*t)$

$\text{ln}(9)=\frac{\text{ln}(3)}{10}*t\cdot\text{ln}(e)$

$\text{ln}(9)=\frac{\text{ln}(3)}{10}*t\cdot1$

$10*\text{ln}(9)=10*\frac{\text{ln}(3)}{10}*t$

$10\text{ln}(9)=\text{ln}(3)*t$

$10\text{ln}(3^2)=\text{ln}(3)*t$

$2\cdot 10\text{ln}(3)=\text{ln}(3)*t$

$20\text{ln}(3)=\text{ln}(3)*t$

Divide both sides by $\text{ln}(3)$ :

$\frac{20\text{ln}(3)}{\text{ln}(3)}=\frac{\text{ln}(3)*t}{\text{ln}(3)}$

$20=t$

Therefore, it will take 20 years for the investment to be $9,000.

5 0

3 years ago

Simplify 3 and 16/24

ad-work [718]

Answer:

4/8 and then 1/2so 1/2 is the final answer

5 0

4 years ago

On Monday, jack and Jill walked from their house up the hill to get to the bus stop. They walked 4 yards every three seconds. Wr

never [62]

Answer: Our required equation will be

$3d=4t$

Step-by-step explanation:

Since we have given that

Jack and Jill walked 4 yards every three seconds

As we know that

$Speed=\frac{Distance}{Time}\\\\Speed=\frac{4}{3}\text{ yards per seconds}\\$

Now, we need to find the find the equation to represent the distance,<em>d</em>,

Jack and Jill walked over time <em>t </em>.

So here it is,

$Distance=Speed\times Time\\\\d=\frac{4}{3}\times t\\\\d=\frac{4}{3}t\\\\3d=4t$

Hence, our required equation will be

$3d=4t$

4 0

3 years ago

Melanie simplified the expression StartStartFraction StartFraction (cotangent (x)) Over (1 Over secant (x)) EndFraction EndEndFr

Leviafan [203]

Answer:

step 4; csc(x)

Step-by-step explanation:

took the test and guessed

8 0

3 years ago

Read 2 more answers