Question

If CB =3(x+8) and AD= 4(x+3), find AB

Answer 1

CD=CA+AB+BD

AB=CD-CA-BD

AB=CD-BD-BD

AB=CD-2.BD

AB=CD-2(BC+CD)

AB=CD-2BC-2CD

AB=-(CD+2BC)

AB=-{98-6(x+8)}

AB= 6x-50