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Tema [17]
3 years ago
11

If CB =3(x+8) and AD= 4(x+3), find AB

Mathematics
1 answer:
kkurt [141]3 years ago
6 0

CD=CA+AB+BD

AB=CD-CA-BD

AB=CD-BD-BD

AB=CD-2.BD

AB=CD-2(BC+CD)

AB=CD-2BC-2CD

AB=-(CD+2BC)

AB=-{98-6(x+8)}

AB= 6x-50

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There are 30 students in Mrs. Martinez's class.
vivado [14]
The answer is 9.
1/5 of 30 is 6.
1/2 of 30 is 15
If you add 6+15=21
And then 30-21=9
So I believe the answer is 9! Hope this helps!! <3
5 0
3 years ago
What is the third quartile of this data set 20,21,24,25,28,29,35,37,42
stepan [7]

Answer:

36

Step-by-step explanation:

The middle number 28 is the median.

The upper quartile is  'middle' number of the last 4 numbers.

So its  the mean of 35 and 37 = 36 (answer)

3 0
3 years ago
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Which of the following are square roots of the number below? Check all that
e-lub [12.9K]
The square root of 196 is 14
4 0
3 years ago
What is the solution set of 2x(x - 1) = 3?
garik1379 [7]

First you must distribute the 2x to the numbers inside the parentheses

(2x * x) + (2x * -1) = 3

2x^{2} - 2x = 3

To make this a quadratic equation you can solve bring the 3 over to the left side of the equation by subtracting it to both sides

2x^{2} - 2x - 3 = 0

Use the quadratic equation to solve this (image of the quadratic equation is below)

Remember that quadratic functions are set up like so:

ax^{2} +bx +c = 0

That means that in this equation...

a = 2

b = -2

c = -3

^^^Plug these numbers into the quadratic equation and solve...

\frac{2+/-\sqrt{(-2)^{2}-4(2)(-3)}}{2(2)}

\frac{2 +/-\sqrt{4+24}}{4}

\frac{2+/-\sqrt{28} }{4}

\frac{2+/-2\sqrt{7} }{4}

\frac{1+/-\sqrt{7} }{2}

Keep in mind that +/- is ±

\frac{1+\sqrt{7} }{2}

\frac{1-\sqrt{7} }{2}

^^^Exact answers

Approximations:

1.823

-0.823

Hope this helped!

~Just a girl in love with Shawn Mendes

8 0
3 years ago
(-5,2) (-5,-1) how to find the slope-intercert form ​
Novay_Z [31]

The slope-intercept form ​of (-5,2) (-5,-1) is undefined

<u>Solution:</u>

Need to find the slope intercept form of line passing through two point (-5,2) (-5,-1).

Slope intercept form of line passing through \left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) is given by

y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\left(x-x_{1}\right)

\text { Here in this problem } \mathrm{x}_{1}=-5, \mathrm{x}_{2}=-5, \mathrm{y}_{1}=2 \text { and } \mathrm{y}_{2}=-1

On Substituting the values we get the slope intercept form of given points,

\begin{array}{l}{y-2=\frac{-3}{0}(x+5)} \\\\ {y-2=-\frac{3(x+5)}{0}}\end{array}

= undefined

Hence the slope intercept form of given points is undefined

3 0
3 years ago
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