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2 years ago

If CB =3(x+8) and AD= 4(x+3), find AB

Mathematics

1 answer:

kkurt [141]2 years ago

6 0

CD=CA+AB+BD

AB=CD-CA-BD

AB=CD-BD-BD

AB=CD-2.BD

AB=CD-2(BC+CD)

AB=CD-2BC-2CD

AB=-(CD+2BC)

AB=-{98-6(x+8)}

AB= 6x-50

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If £2000 is placed into a bank account that pays 3% compound interest per year,

Anastaziya [24]

5500 is the awnser I came up with

5 0

3 years ago

What is the common ratio between successive terms in the sequence? 27,9,3,1, 1/3, ,1/9, 1/27

tigry1 [53]

Answer:

1/3

Step-by-step explanation:

Take the second term and divide by the first

9/27 = 1/3

Take the third term and divide by the second

3/9 = 1/3

Check each subsequent ratio, we can see the common ratio is 1/3

4 0

3 years ago

The principal P is borrowed and the loan's future value A at time t is given. Determine the loan's simple interest rate r.

Virty [35]

A = P + SI

A-P = SI

5425-5000 = 425

THEREFORE THE SIMPLE INTRESTE IS $425

SI = PTR/100

425 = 5000×1×R/100

425×100/5000×1=R

425×100÷5,000×1 = 8.5%

THEREFORE THE RATE IS 8.5%

8 0

3 years ago

The average daily jail population in the United States is 706,242. If the distribution is normal and the standard deviation is 5

Karolina [17]

a. The probability that on a randomly selected day, the jail population

is greater than 750,000 is 20.1%

b. The probability that on a randomly selected day, the jail population is

between 600,000 and 700,000 is 43.2%

Step-by-step explanation:

The given is:

1. The average daily jail population in the United States is 706,242

2. The distribution is normal and the standard deviation is 52,145

3. We need to find the probability that on a randomly selected day,

the jail population is greater than 750,000

4. We need to find the probability that on a randomly selected day,

the jail population is between 600,000 and 700,000

At first find z-score

∵ z = (x - μ)/σ, where x is the score, μ is the mean and σ is the standard

deviation

∵ x = 750,000 , μ = 706,242 and σ = 52,145

∴ z = $\frac{750,000-706,242}{52,145}$ ≅ 0.84

Use the normal distribution table of z to find the area to the right of

the z-value

∵ The corresponding area to z-score of 0.84 is 0.79955

- But we are interested in x > 750,000, we need the area to the

right of z-score

∴ P(x > 750,000) = 1 - 0.79955 = 0.2005

∴ P(x > 750,000) = 0.2005 × 100% = 20.1%

The probability that on a randomly selected day, the jail population is

greater than 750,000 is 20.1%

We will find z-score for 600,000 < x < 700,000

∵ z = $\frac{600,000-706,242}{52,145}$ ≅ -2.04

∵ z = $\frac{700,000-706,242}{52,145}$ ≅ -0.12

Use the normal distribution table of z to find the area between

the two z-values

∵ The corresponding area to z-score of -2.04 is 0.02068

∵ The corresponding area to z-score of -0.12 is 0.45224

- To find P(600,000 < x < 700,000) subtract the two values above

∴ P(600,000 < x < 700,000) = 0.45224 - 0.02068 = 0.4316

∴ P(600,000 < x < 700,000) = 0.4316 × 100% = 43.2%

The probability that on a randomly selected day, the jail population is

between 600,000 and 700,000 is 43.2%

Learn more:

You can learn more about z-score in brainly.com/question/7207785

#LearnwithBrainly

5 0

3 years ago

The gravitational force exerted by the planet Earth on a unit mass at a distance r from the center of the planet is:

jolli1 [7]

Answer:

Yes, F is a continuous function of r

Step-by-step explanation:

We are given that

When r<R

$F(r)=\frac{GMr}{R^3}$

$r\geq R$

$F(r)=\frac{GM}{r^2}$

Where M=Mass of the earth

R=Radius of earth

G=Gravitational constant

We have to find the function is continuous of r or not.

LHL

$\lim_{r\rightarrow R-}\frac{GMr}{R^3}=\frac{GMR}{R^3}=\frac{GM}{R^2}$

RHL

$\lim_{r\rightarrow R+}\frac{GM}{R^2}=\frac{GM}{R^2}$

$F(R)=\frac{GM}{R^2}$

When a function is continuous at x=a

Then, LHL=RHL=f(a)

RHL==LHL=F(R)

Hence, the function is continuous of r.

8 0

3 years ago