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3 years ago

If CB =3(x+8) and AD= 4(x+3), find AB

Mathematics

1 answer:

kkurt [141]3 years ago

6 0

CD=CA+AB+BD

AB=CD-CA-BD

AB=CD-BD-BD

AB=CD-2.BD

AB=CD-2(BC+CD)

AB=CD-2BC-2CD

AB=-(CD+2BC)

AB=-{98-6(x+8)}

AB= 6x-50

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There are 30 students in Mrs. Martinez's class.

vivado [14]

The answer is 9.
1/5 of 30 is 6.
1/2 of 30 is 15
If you add 6+15=21
And then 30-21=9
So I believe the answer is 9! Hope this helps!! <3

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3 years ago

What is the third quartile of this data set 20,21,24,25,28,29,35,37,42

stepan [7]

Answer:

Step-by-step explanation:

The middle number 28 is the median.

The upper quartile is 'middle' number of the last 4 numbers.

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3 years ago

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Which of the following are square roots of the number below? Check all that

e-lub [12.9K]

The square root of 196 is 14

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3 years ago

What is the solution set of 2x(x - 1) = 3?

garik1379 [7]

First you must distribute the 2x to the numbers inside the parentheses

(2x * x) + (2x * -1) = 3

$2x^{2}$ - 2x = 3

To make this a quadratic equation you can solve bring the 3 over to the left side of the equation by subtracting it to both sides

$2x^{2}$ - 2x - 3 = 0

Use the quadratic equation to solve this (image of the quadratic equation is below)

Remember that quadratic functions are set up like so:

$ax^{2} +bx +c = 0$

That means that in this equation...

a = 2

b = -2

c = -3

^^^Plug these numbers into the quadratic equation and solve...

$\frac{2+/-\sqrt{(-2)^{2}-4(2)(-3)}}{2(2)}$

$\frac{2 +/-\sqrt{4+24}}{4}$

$\frac{2+/-\sqrt{28} }{4}$

$\frac{2+/-2\sqrt{7} }{4}$

$\frac{1+/-\sqrt{7} }{2}$

Keep in mind that +/- is ±

$\frac{1+\sqrt{7} }{2}$

$\frac{1-\sqrt{7} }{2}$

^^^Exact answers

Approximations:

1.823

-0.823

Hope this helped!

~Just a girl in love with Shawn Mendes

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3 years ago

(-5,2) (-5,-1) how to find the slope-intercert form

Novay_Z [31]

The slope-intercept form of (-5,2) (-5,-1) is undefined

<u>Solution:</u>

Need to find the slope intercept form of line passing through two point (-5,2) (-5,-1).

Slope intercept form of line passing through $\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)$ is given by

$y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\left(x-x_{1}\right)$

$\text { Here in this problem } \mathrm{x}_{1}=-5, \mathrm{x}_{2}=-5, \mathrm{y}_{1}=2 \text { and } \mathrm{y}_{2}=-1$

On Substituting the values we get the slope intercept form of given points,

$\begin{array}{l}{y-2=\frac{-3}{0}(x+5)} \\\\ {y-2=-\frac{3(x+5)}{0}}\end{array}$

= undefined

Hence the slope intercept form of given points is undefined

3 0

3 years ago