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2 years ago

Identify the function of the transformation

Mathematics

1 answer:

ExtremeBDS [4]2 years ago

7 0

|x| - 1 because you moved down 1 unit

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The table below represents an exponential function what is the common ratio

Greeley [361]

Solution:

Given:

A table representing an exponential function.

The x-values represent the terms, while the y-values represent the numbers.

The common ratio is gotten from the numbers (y-values).

The formula for common ratio is given by;

$\begin{gathered} r=\frac{present\text{ term}}{preceed\text{ ing term}} \\ \\ \text{Hence,} \\ r=\frac{108}{36}=\frac{36}{12}=\frac{12}{4}=\frac{4}{1.33\ldots}=\frac{1.33\ldots.}{0.44\ldots} \\ r=3 \end{gathered}$

Therefore, the common ratio is 3.

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1 year ago

Ten years ago, only 20% of the u.s. population consisted of people more than 65 years old. a researcher plans to use a sample of

Strike441 [17]

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2 years ago

Read 2 more answers

The length of a line is y centimetres.

ElenaW [278]

Answer:

10y mm

Step-by-step explanation:

We would need to know the conversion of cm to mm.

We know

1 cm = 10 mm

If we are given a certain amount of centimeters (cm), to get the answer in millimeters (mm), we multiply that by 10. Example:

1 cm = 10 mm

4 cm would be 4 * 10 = 40 mm

23 cm would be 23 * 10 = 230 mm

Now, we are given "y" centimeters.

So, we multiply by "10" to get the answer in millimeters.

Hence,

y * 10 = 10y millimeters (mm)

The line is 10y mm

3 0

2 years ago

Find the image of mc016-2.jpgDEF under the translation of (x, y) mc016-3.jpg (x + 7, y + 2).

erica [24]

(7,2) is the answer.
There you go.

4 0

3 years ago

Use cylindrical coordinates. Find the volume of the solid that lies within both the cylinder x2 + y2 = 25 and the sphere x2 + y2

Inessa05 [86]

Answer:

Step-by-step explanation:

we are asked to find the volume of solid that lies within both the cylinder

$x^2 + y^2 = 25$

and

the sphere $x^2 + y^2 + z^2 = 49.$

Conversion from rectangular to cylindrical is

$x=rcost\\y = rsint\\z=z$

|J| =r

In cylindrical coordinates the volume is bounded by the cylinder r=5 and

$r^2+z^2 =49$

Hence we can write volume as

$\int \int \int dxdydz\\=\\\int _0^5 \int_0^{2\pi} \int_{-\sqrt{49-r^2} } ^{\sqrt{49-r^2} rdzdtdr\\= 2\pi \int _0^5 (2\sqrt{49-r^2} rdr\\=4\pi (-(49-r^2) (2/3)\\= \frac{4\pi}{3} (343-48\sqrt{6} )$

6 0

3 years ago