Answer:
(A) 2/3 [√(4-4x)]^3
(B) 2/3 [√(4-x)]^3
Step-by-step explanation:
Integrating the functions,
(A) Any function in square root is equal to or same as the function raised to the power of 1/2
To integrate, add 1 to the power of the function. That's 1/2 + 1 = 3/2
Divide the function by this new power 3/2. This implies multiplying the function by the inverse of 3/2. The inverse of 3/2 is 2/3.
Also, when a function is raised to the power of a fraction instead of a whole number, you take the 'denominator' root of the function, and then raise the function to the power of the numerator.
Here, the denominator is 2, so you take the square root of the function, and raise the function to the power of 3
So the integral of Y = √[4-4x] is
2/3 [√(4-4x)]^3
(B) In like manner, the integral of
Y = √[4-x] is
2/3 [(√4-x)]^3
Answer:
surface area of cube is 6a² where a is side of the cube
Not sure what you mean by drag and drop but Im going to attempt this.
-3/5 = -12/20
1/5 = 4/20
That makes no sense. It should be -8/20 < 7/20?
Answer:
b < -1
Step-by-step explanation:
Step 1: Write inequality
-3(6b - 1) > 18 - 3b
Step 2: Solve for <em>b</em>
<u>Distribute -3:</u> -18b + 3 > 18 - 3b
<u>Add 18b to both sides:</u> 3 > 18 + 15b
<u>Subtract 18 on both sides:</u> -15 > 15b
<u>Divide both sides by 15:</u> -1 > b
<u>Rewrite:</u> b < -1
Answer:
Can you add a picture or visual model if there is one?
Step-by-step explanation: