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kvv77 [185]
3 years ago
12

Chris types at an average speed of 50 words per minute. He has already typed 1,250 words of his final paper. The paper has to be

Mathematics
1 answer:
Anna11 [10]3 years ago
8 0

Answer:

D. 50x+1,250>3,750

Step-by-step explanation:

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In the formula A(t) = A0ekt, A(t) is the amount of radioactive material remaining from an initial amount A0 at a given time t an
Alenkasestr [34]

Answer:  693 years

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:

A(t) =A_0e^{kt}

k = rate constant

t = time taken for decomposition = 1

A_0 = Initial amount of the reactant

A_t = amount of the reactant left =A_0-\frac{0.1}{100}\times A_0=0.999A_0

0.999A_0=A_0e^{k\times 1}

0.999=e^k

k=-0.001year^{-1}

for half life : t=t_\frac{1}{2}

A_t=\frac{1}{2}A_o

Putting in the values , we get

\frac{1}{2}A_0=A_0e^{-0.001\times t_\frac{1}{2}

t_\frac{1}{2}=693 years

Thus half life of this isotope, to the nearest year is 693.

8 0
3 years ago
The length of a rectangular is 5/2 unites greater then twice its width if it’s width w which expression gives the perimeter of t
strojnjashka [21]

If width is w the length can be represented as 5/2+2w.

Formula for perimeter is 2l + 2w

So it would be 2w + 2(5/2 + 2w)

OR 2w + 5 + 4w

OR 6w + 5



See if this helps ;)

5 0
3 years ago
HELP !!!! find the measurements of each angle
telo118 [61]
1 is 52 2 is 30 3 is 30 4 is 62 5 is 118
8 0
3 years ago
Find two numbers if their sum is 6.1 and their difference is 1.6
Radda [10]
For this case, the first thing we must do is define variables:
 x: unknown number (1)
 y: unknown number (2)
 We now write the equations that model the problem:
 their sum is 6.1:
 x + y = 6.1

 their difference is 1.6:
 x - y = 1.6

 Solving the system we have:
 We add both equations:
 x + x = 6.1 + 1.6

2x = 7.7

x = 7.7 / 2

x = 3.85
 Then, we look for the value of y using any of the equations:
 x - y = 1.6

y = x - 1.6

y = 3.85 - 1.6

y = 2.25
 Answer:
 
The numbers are:
 
x = 3.85

y = 2.25
6 0
3 years ago
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