9514 1404 393
Answer:
- 3 big bucks
- 6 little bucks
- 17 does
Step-by-step explanation:
Let B, L, D represent the numbers of big bucks, little bucks, and does, respectively.
B + L + D = 26 . . . . . . total bagged
D = 5 + 2L . . . . . . . . . 5 more does than twice the number of little bucks
B = L/2 . . . . . . . . . . . . half as many big bucks as little bucks
__
We can substitute for B and D in the first equation:
L/2 + L + (5 +2L) = 26
7/2L = 21 . . . . . . . . . . . . . subtract 5, collect terms
L = 6 . . . . . . . . . . . . . . . . . multiply by 2/7
D = 5 + 2·6 = 17
B = 6/2 = 3
The party bagged 3 big bucks, 6 little bucks and 17 does.
