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Liula [17]
3 years ago
12

PLEASE ANSWER ASASP!!!!!!!!!!!!!!!

Mathematics
1 answer:
Maksim231197 [3]3 years ago
3 0

Answer: i would say lawrence

Step-by-step explanation:

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A rhombus has the same properties as a square. True False
sukhopar [10]

Answer: True

Step-by-step explanation: am i wrong

7 0
3 years ago
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There is a number that if you multiply it by 4 first, and then subtract 10 from the result, you get 14. What's the number.
polet [3.4K]
It's 6. 6 times 4 is 24, and 24 minus 10 is 14
6 0
4 years ago
Please help!
Gemiola [76]

The derivative of f(x) = 2\cdot x^{2}-9 is f'(x) = 4\cdot x.

In this exercise we must apply the definition of derivative, which is described below:

f'(x) =  \lim_{x \to 0} a_n \frac{f(x+h)-f(x)}{h} (1)

If we know that f(x) = 2\cdot x^{2}-9, then the derivative of the expression is:

f'(x) =  \lim_{h \to 0} \frac{2\cdot (x+h)^{2}-9-2\cdot x^{2}+9}{h}

f'(x) = 2\cdot \lim_{h \to 0} \frac{x^{2}+2\cdot h\cdot x + h^{2}-2\cdot x^{2}}{h}

f'(x) = 2\cdot  \lim_{h \to 0} 2\cdot x + h

f'(x) = 4\cdot x

The derivative of f(x) = 2\cdot x^{2}-9 is f'(x) = 4\cdot x.

We kindly invite to check this question on derivatives: brainly.com/question/23847661

4 0
3 years ago
What is the equation of this graphed line?
Anettt [7]
Download here


Because the certain point
3 0
3 years ago
Pls solve this ,urgent no spam​
aleksklad [387]

Answer:

<u>Question 3</u>

Given expression:

\sf \left(\dfrac{-8}{9} \times \dfrac{1}{-5}\right)+\left(\dfrac{-8}{9} \times \dfrac{-7}{11}\right)

Both parentheses share a common term.

To factor out a common term: ab + ac = a(b + c)

\textsf{Factor out the common term }\dfrac{-8}{9}

\sf \implies\dfrac{-8}{9} \times \left(\dfrac{1}{-5}+\dfrac{-7}{11}\right)

-------------------------------------------------------------------------------------------------

<u>Question 4</u>

To calculate the amount of money Rajni had to begin with, sum the three amounts she spent:

\sf \implies total=10\frac14+25\frac34+16\frac12

As \sf a\frac{b}{c}=a+\frac{b}{c}, then:

\sf \implies 10+\frac14+25+\frac34+16+\frac12

Collect and sum the whole numbers:

\sf \implies (10+25+16)+\frac14+\frac34+\frac12

\sf \implies 51+\frac14+\frac34+\frac12

As  \sf \frac14+\frac34=\frac44=1, then

\sf \implies 51+1+\frac12

\sf \implies 52+\frac12

\sf \implies 52\frac12

4 0
2 years ago
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