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Natali5045456 [20]
3 years ago
5

Rose bought 5 large box lunches for $50. Which equation can be used to find the total cost, L, of a large box lunch?

Mathematics
2 answers:
vova2212 [387]3 years ago
4 0

Answer:

L= 50 divided by 5

Softa [21]3 years ago
3 0

Answer:

L=10*x

X being the total number of box lunches

In this case L=10*5 = 50

Step-by-step explanation:

Total cost =L

1 large box lunch = 50/5=10

Therefore the total cost would be

L=10*X

x being the total number of box lunches

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Divide using any method. .<br> -3.23 + 4x2 + 2x – 5)<br> 2
stepladder [879]

Answer:

Step-by-step explanation:

-3x^2 --2x--2 -- 9/x--2

3 0
3 years ago
Horizontal stadia sights. Determine the error in distance if the uppermost portion of a 3. 0m long stadia rod is inclined 14 cm
jek_recluse [69]

The error in the distance if the uppermost portion of a 3. 0m long stadia rod is inclined 14 cm toward the observer and the rod intercept is 1. 75m on a horizontal sight is 8.167cm.

<h3>What is Tangent (Tanθ)?</h3>

The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. it is given as,

Tan(θ) = Perpendicular/Base

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The base is the adjacent smaller side of the angle θ.

Given the uppermost portion of a that is 3.0m long stadia rod is inclined 14 cm toward the observer, therefore, the angle of inclination, θ can be written as

tan(θ)=0.14/3

θ = 2.672°

Also, the rod intercept is 1.75m, therefore, t the error in distance in the distance is,

tanθ=x/1.75

x = 1.75 tan(θ)

x = 1.75 × tan(2.672°)

x = 0.08167 m = 8.167 cm

Hence, the error in the distance if the uppermost portion of a 3. 0m long stadia rod is inclined 14 cm toward the observer and the rod intercept is 1. 75m on a horizontal sight is 8.167cm.

Learn more about Tangent (Tanθ):

brainly.com/question/10623976

#SPJ4

6 0
2 years ago
Nate is making a picture frame by cutting a small rectangular prism out of a larger rectangular prism. When the project is compl
dybincka [34]
Surface area= [15*3*2]+[20*3*2]+[10*3*2]+[14*3*2]+[15*3*2]+[14*2.5*2]

surface area=90+120+60+84+90+70=514 in²

the answer is 514 in²
6 0
3 years ago
Quadrilateral $abcd$ is a trapezoid with $ab$ parallel to $cd$. we know $ab = 20$ and $cd = 12$. what is the ratio of the area o
alekssr [168]
Draw a diagram to illustrate the problem as shown below.

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A₁ = (1/2)*20*h = 10h

The area of trapezoid abcd is
A₂ = (1/2)*(20+12)*h = 16h

The ratio A₁/A₂ is
A₁/A₂ = (10h)/(16) = 5/8

Answer:
The ratio of triangle acb to the area of trapezoid abcd is 5/8.

4 0
4 years ago
If 3x – 2 = 13, what is the value of x?
inessss [21]

Answer:

x = 5

Step-by-step explanation:

3x - 2 = 13 \\ 3x = 13 + 2 \\ 3x = 15 \\ x =  \frac{15}{3} \\ \huge \red{ \boxed{ x = 5 }}

8 0
3 years ago
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