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ad-work [718]
3 years ago
15

Dada la circunferencia de ecuación x 2 +y 2 -2x+4y-4=0, hallar el centro y el radio.

Mathematics
1 answer:
Anna11 [10]3 years ago
4 0

La forma estándar de una ecuación de un círculo es% 28x-h% 29% 5E2 +% 2B +% 28y-k% 29% 5E2 + = + r% 5E2

donde Pt (h, k) es el centro y r es el radio

x ^ 2 + y ^ 2-10x + 4y + 4 = 0

completando los cuadrados para ponerlos en la forma estándar

x ^ 2 -10x + y ^ 2 + 4y + 4 = 0

(x-5) ^ 2-25 + (y +2) ^ 2-4 + 4 = 0

 (x-5) ^ 2 + (y + 2) ^ 2 = 25

El centro es (5, -2) radio = 5

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In 1982 Abby’s mother scored at the 93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the
oksian1 [2.3K]

Answer:

The percentle for Abby's score was the 89.62nd percentile.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation(which is the square root of the variance) \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Abby's mom score:

93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the scores was 9604.

93rd percentile. X when Z has a pvalue of 0.93. So X when Z = 1.476.

\mu = 503, \sigma = \sqrt{9604} = 98

So

Z = \frac{X - \mu}{\sigma}

1.476 = \frac{X - 503}{98}

X - 503 = 1.476*98

X = 648

Abby's score

She scored 648.

\mu = 521 \sigma = \sqrt{10201} = 101

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{648 - 521}{101}

Z = 1.26

Z = 1.26 has a pvalue of 0.8962.

The percentle for Abby's score was the 89.62nd percentile.

3 0
3 years ago
How many ways can three different numbers be selected from 10 numbers to open a keypad lock?
Paraphin [41]

There are 720 ways through which 3 numbers can be selected from 10 numbers to open a keypad lock.

Given that there are 10 numbers are 3 numbers are required to open a keypad lock.

Permutations are the number of ways in which objects can be selected without replacements to form subsets.

It is expressed as nP_{r}=n!/(n-r)!.

Factorial of a number is the product of consecutive numbers less than the number.

Total numbers available=10

Numbers to be selected=3

Number of ways can be found by using permutations.

Number of ways =10P_{3}

=10!/(10-3)!

=10!/7!

=10*9*8*7!/7!

=10*9*8

=720 ways.

Hence there are 720 ways through which 3 numbers can be selected from 10 numbers.

Learn more about permutations at brainly.com/question/1216161

#SPJ1

6 0
2 years ago
Suppose you want to be sure that the total cost of the three items does not go over a certain amount. How can you use estimation
Bond [772]

Answer:

i don't konw

Step-by-step explanation:

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3 years ago
Gets Brainliest and 11pts!
belka [17]

Volume sphere A V1 = (4/3)πR³

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r=∛((3/4)V2/π)

R-r = ∛((3/4)40/π) - ∛((3/4)10/π) ≈ 0.8 inch

Answer C. 0.8 inch.

7 0
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Answer:

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Step-by-step explanation:

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