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3 years ago

7

Of the 850 runners in a race, 137 are men and the rest are women. What is the ratio of the number of female runners to the total

number of runners?

2 answers:

Masteriza [31]3 years ago

6 0

Answer:

Unsimplified answer

713:850

Step-by-step explanation:

850-137=713

713:850

Margaret [11]3 years ago

3 0

It would be 713:850 because you subtract the men from the total

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Ava borrowed some money from her friend in order to help buy a new video game system. Ava agreed to pay back her friend $2 per w

nydimaria [60]

We know that Ava is paying $2 dollars per week so if L is the money that she owes and t is the number of weeks, and I is the initial debt so we can write an equation like:

$L=I-2t$

Now we can replace the info we have to find the value of I so:

$10=I-2(5)$

and we solve for I

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1 year ago

Lamar used 7/8 of a cup of raisins to make snacks mix. he used 3/4 of a cup of raisins to make cookies what expression could be

Alinara [238K]

The answer is B.

In order to add the two values together, you must find the least common multiple for the denominators. The denominators are 8 and 4, and the least common multiple of 8 and 4 is 8. Because you have to multiply 4 by 2 to get 8, you must also multiply 3 by 2 to get 6. This will give you 6/8.

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2 years ago

What is the coordinates of the center of an ellipse defined by the equation 16x^2 + 25y^2 + 160x - 200y + 400 = 0 ? Please give

pickupchik [31]

16x^2 + 25y^2 + 160x - 200y + 400 = 0     Rearrange and regroup.

(16x^2 + 160x) + (25y^2 - 200y ) = 0-400.     Group the xs together and the ys together.

16(X^2 + 10x) + 25(y^2-8y) = -400.     Factorising.

We are going to use completing the square method.

Coefficient of x in the first expression = 10.

Half of it = 1/2 * 10 = 5. (Note this value)

Square it = 5^2 = 25.     (Note this value)

Coefficient of y in the second expression = -8.

Half of it = 1/2 * -8 = -4. (Note this value)

Square it = (-4)^2 = 16. (Note this value)

We are going to carry out a manipulation of completing the square with the values

25 and 16. By adding and substracting it.

16(X^2 + 10x) + 25(y^2-8y) = -400

16(X^2 + 10x + 25 -25) + 25(y^2-8y + 16 -16) = -400

Note that +25 - 25 = 0.    +16 -16 = 0. So the equation is not altered.

16(X^2 + 10x + 25) -16(25) + 25(y^2-8y + 16) -25(16) = -400

16(X^2 + 10x + 25) + 25(y^2-8y + 16) = -400 +16(25) + 25(16)    Transferring the terms -16(25) and -25(16)

to other side of equation. And 16*25 = 400

16(X^2 + 10x + 25) + 25(y^2-8y + 16) = 25(16)

16(X^2 + 10x + 25) + 25(y^2-8y + 16) = 400

We now complete the square by using the value when coefficient was halved.

16(x-5)^2 + 25(y-4)^2 = 400

Divide both sides of the equation by 400

(16(x-5)^2)/400 + (25(y-4)^2)/400 = 400/400              Note also that, 16*25 = 400.

((x-5)^2)/25 + ((y-4)^2)/16 = 1

((x-5)^2)/(5^2) + ((y-4)^2)/(4^2) = 1

Comparing to the general format of an ellipse.

((x-h)^2)/(a^2) + ((y-k)^2)/(b^2) = 1

Coordinates of the center = (h,k).

Comparing   with above   (x-5) = (x - h) , h = 5.

Comparing   with above   (y-k) = (y - k) , k = 4.

Therefore center = (h,k) = (5,4).

Sorry the answer came a little late. Cheers.

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3 years ago

Find three ordered pairs for x=9

MariettaO [177]

Three examples are (9, 1), (9, -5), and (9, 3.2).

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3 years ago

第 5 个问题 a multiple choice exam has 10 questions. each question has 3 possible answers, of which one is correct. a student knows

tatuchka [14]

The chances that the student was merely guessing is 1/3.

Bayes Theorem determines the conditional probability of an event A given that event B has already occurred.

denoted by

$P(A/B)=\frac{P(A)*P(B/A)}{P(B)}$

let A be the event that the student knows the answer .

B be the event that the student does not knows the answer .

and

E be the event he gets answer correct .

According to the given question

$P(A)=\frac{4}{10} \\\\ P(B)=1-\frac{4}{10} =\frac{6}{10}$

Probability that the answer is correct ,given that he knows the answer is

$P(E/A)=1$

Probability that the answer is correct ,given that he guesses it is

$P(E/B)=\frac{1}{3}$ [as the MCQ has 3 options and only one is correct]

We need to find the probability that he guesses the answer given that it is correct.

Required probability $P(B/E)=\frac{P(B)*P(E/B)}{P(A)*P(E/A)+P(B)*P(E/B)}$

Substituting the values we get

$P(B/E)=\frac{\frac{6}{10} *\frac{1}{3} }{\frac{4}{10} *1+\frac{6}{10} *\frac{1}{3} }$

$=\frac{6}{30}*\frac{30}{18} \\ \\ =\frac{6}{18} \\ \\ =\frac{1}{3}$

Therefore , the chances that the student was merely guessing is 1/3.

Learn more about Probability here brainly.com/question/13140147

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