<span>12a^3b + 8a^2b^2 − 20ab^3
</span>12a^3b = 4ab(3a^2)
8a^2b^2 = 4ab(2ab)
20ab^3 = 4ab(5b^2)
GCF = 4ab
12a3b + 8a2b2 − 20ab3 = 4ab(3a^2 + 2ab - 5b^2)
8 divided by 42 = 5.25 which means you spent $5.25 on each ticket
Answer:3/2
Step-by-step explanation:
6/10 ➗ 2/5
6/10 x 5/2
(6x5)/(10x2)
30/20=3/2
Answer:
D.
Step-by-step explanation:
Remember that the limit definition of a derivative at a point is:
![\displaystyle{\frac{d}{dx}[f(a)]= \lim_{x \to a}\frac{f(x)-f(a)}{x-a}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28a%29%5D%3D%20%5Clim_%7Bx%20%5Cto%20a%7D%5Cfrac%7Bf%28x%29-f%28a%29%7D%7Bx-a%7D%7D)
Hence, if we let f(x) be ln(x+1) and a be 1, this will yield:
![\displaystyle{\frac{d}{dx}[f(1)]= \lim_{x \to 1}\frac{\ln(x+1)-\ln(2)}{x-1}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%281%29%5D%3D%20%5Clim_%7Bx%20%5Cto%201%7D%5Cfrac%7B%5Cln%28x%2B1%29-%5Cln%282%29%7D%7Bx-1%7D%7D)
Hence, the limit is equivalent to the derivative of f(x) at x=1, or f’(1).
The answer will thus be D.
Answer:
50
Step-by-step explanation:
x = √30² - 18² = √576 = 24
tan A = 18/24 = 3/4
∠A = ∠B
tan B = tan A = 24 / y = 3 / 4
y = (24 x 4) / 3 = 32
Z = y + 18 = 32 + 18 = 50