Question

An elevator in a mine shaft is stopped at a .25 feet below ground level. And then travels 28 feet downward. What equation can be written to find the final position in feet of the elevator in relations to ground level?

Answer 1

Correct question:

An elevator in a mine shaft is stopped at 25 feet below ground level. And then travels 28 feet downward. What equation can be written to find the final position in feet of the elevator in relations to ground level?

Answer:

-53 feets

Step-by-step explanation:

Initial stop point = 25 feets below ground level

Further distance traveled = 28 feets below ground level

Final position in feet = Initial stop point + further distance traveled

Note : distances or point traveled below ground level or downward is represented as negative.

Final position in feets = (-25)feets + (-28)feets

Final position in feets = - 53 feets