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3 years ago

Please help!!!!!!!!!!

Mathematics

1 answer:

topjm [15]3 years ago

3 0

Ah yes, good ol’ Pythagorean’s theorem.

The hypotenuse is the opposite of the 90 degree angle, the longest side of the triangle.

The legs are opposite of the acute angles

Formula: a^2 + b^2 = c^2

2:

Let’s plug in some values

(6)^2 + (3)^2 = c^2

C = 6.7

The side will be 6.7 units

3)

Let’s plug in some values

(13.3)^2 = (9.7)^2 + (b)^2

(13.3)^2 - (9.7)^2 = b^2

176.89 - 94.09 = b^2

b = 9.1

The side will be 9.1 units

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In one year the perseid metor shower had a metor appear every 1/5 5 minutes on average That same year the Leonid metor shower ha

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In one year, the Perseid meteor shower had a meteor appear every 1 1/5 minutes on average. That same year, the Leonid meteor shower had a meteor appear every 4 2/3 minutes on average. How many more meteors fell during the Perseid meteor shower?

Answer:

325,452 meteors

Step-by-step explanation:

We all know that :

We have 365 days in a year and in each day there are 24 hours, Likewise an hour has 60 minutes

SO, the total number of minutes in a year is :

365 × 24 × 60 = 525600 minutes

For Perseid meteor:

$1 + \frac{1}{5} \\ \\ = 1 + 0.2 \\ \\ = 1.2$

So one meteor fall at 1.2 minutes interval Thus, in a year, we will have :

1 meteor - 1.2 minutes.

x meteor - 525600 minutes.

1.2x = 525600

$x = \frac{525600}{1.2}$

x = 438000

∴ 438,000 meteors fell during the Perseid shower.

For Leonid meteor shower:

$4 + \frac{2}{3} = 4.67$

So one meteor fall at 4.67 minutes interval Thus, in a year, we will have :

1 meteor - 4.67 minutes.

x meteors - 525600 minutes.

$4.67x = 525600$

$x = \frac{525600}{4.67}$

x = 112548

112,548 meteors fell during the Leonid Shower.

Finally , the numbers of more meteors that fell during the Perseid meteor shower is calculated by the difference in the number of Perseid meteor shower and Lenoid meteor shower. i.e

438,000 - 112,548 = 325,452

325,452 more meteors fell during the Perseid meteor shower

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