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2 years ago

13

The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0.43. The mass of the object i

s 4.1kg. What is the force of friction?

1 answer:

brilliants [131]2 years ago

7 0

Answer:

14 x 0.27 = 3.78 is your answer

Explanation:

the question is asking for the weight of the object so you multiply and get 3.79

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in rectangle PQRS, shown below, the diagonal PR is 15 meters. if the sine of angle SPR is 7/10, what is the value of RS?

lora16 [44]

Answer:sin =perpendicular/hypotenuse

Step-by-step explanation:

Sin angle is given use tan theta or cos theta to find the RS

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2 years ago

If f(3)=2x^3 -2 , what is the value of f(2)

iris [78.8K]

I'm not sure about this but will give it a try:

Let f(n) = 2xⁿ - 2

Then f(3) = 2x³ - 2

So, f(2) = 2x² - 2

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2 years ago

Completely factor and simplify the expression 3x - 9y

mr Goodwill [35]

Your answer is 3(x-3y)

3 0

3 years ago

Pls can someone help me<br><img src="https://tex.z-dn.net/?f=%20log10%20%5Csqrt%7B36%7D%20%20%2B%20%20%20%20log10%20%20%5Csqrt%7

Firlakuza [10]

Answer:

$= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

Step-by-step explanation:

Given the expression $log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\$

According to the law of logarithm;

loga + log b = log(ab) and log a - log b = log(a/b)

The given expression becomes;

$log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\= log_{10}(\frac{\sqrt{36} \times \sqrt{2} }{\sqrt{7} })\\= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

6 0

2 years ago

Mr.Ward runs a lot. He ran 45 minutes each day, 5 days each week , for 16 weeks . In that time, he ran 450 miles. What was his a

Savatey [412]

Answer:

7.5 miles per hour.

Step-by-step explanation:

We have been given that Mr. Ward runs a lot. He ran 45 minutes each day, 5 days each week, for 16 weeks.

First of all, we will find time for that Mr. Ward ran in 16 weeks.

We will multiply 5 by 16 to find number of days for that Mr. Ward ran and then we will multiply the result by 45 minutes to find the time.

$\text{Time for that Mr. Ward ran in 16 weeks}=16\times 5\times 45\text{ minutes}$

$\text{Time for that Mr. Ward ran in 16 weeks}=3600\text{ minutes}$

Now, we will divide 3600 minutes by 60 minutes to convert time into hours as:

$\text{Hours}=\frac{3600}{60}=60$

Now, we will divide 450 miles by 60 hours to find Mr. Ward's average speed as:

$\text{Mr. Ward's average speed}=\frac{450\text{ miles}}{\text{60 hours}}$

$\text{Mr. Ward's average speed}=\frac{7.5\text{ miles}}{\text{ Hour}}$

Therefore, Mr. Ward's average speed in 7.5 miles per hour.

7 0

2 years ago