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3 years ago

Could someone please help? What is the scale factor of the dilation shown?

Mathematics

1 answer:

aalyn [17]3 years ago

4 0

Answer:

C: 3/4

Step-by-step explanation:

Hopefully this helps!

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Mr. Dion is the band director at school. He asks students

Agata [3.3K]

I think B I’m
Not
Sue tho so don’t take my word on it but I think it’s B

8 0

2 years ago

Simplify this equation<br> (3X^2+21X+33)/(X+5)

Amiraneli [1.4K]

Answer:

(3x^2+21x+33) / (x+5)

You can use long division:

(3x^2+21x+33)

--------------------

(x+5)

=3x+6+ 3/x+5

Step-by-step explanation:

6 0

3 years ago

If f(x) = 4* + 12x and g(x) = 5x - 1, find (f + g)(x).

Rudik [331]

Answer:

$\large\boxed{(f+g)(x)=4^x+17x-1}$

Step-by-step explanation:

$(f+g)(x)=f(x)+g(x)\\\\f(x)=4^x+12x,\ g(x)=5x-1\\\\(f+g)(x)=(4^x+12x)+(5x-1)=4^x+17x-1$

4 0

3 years ago

Health insurers are beginning to offer telemedicine services online that replace the common office visit. A company provides a v

Veronika [31]

Answer:

$\text {CI} = (60.54, \: 81.46)\\\\$

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

Step-by-step explanation:

Let us find out the mean savings for a televisit to the doctor from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

$\bar{x} = \$71$

Let us find out the standard deviation of savings for a televisit to the doctor from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

$s = \$ 22.35$

The confidence interval is given by

$\text {confidence interval} = \bar{x} \pm MoE\\\\$

Where the margin of error is given by

$$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\$

Where n is the sample of 20 online doctor visits, s is the sample standard deviation and $t_{\alpha/2}$ is the t-score corresponding to a 95% confidence level.

The t-score is given by is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 20 - 1 = 19

From the t-table at α = 0.025 and DoF = 19

t-score = 2.093

So, the margin of error is

$MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 2.093\cdot \frac{22.35}{\sqrt{20} } \\\\MoE = 2.093\cdot 4.997\\\\MoE = 10.46\\\\$

So the required 95% confidence interval is

$\text {CI} = \bar{x} \pm MoE\\\\\text {CI} = 71 \pm 10.46\\\\\text {CI} = 71 - 10.46, \: 71 + 10.46\\\\\text {CI} = (60.54, \: 81.46)\\\\$

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

7 0

3 years ago

Wday is the area in square inches of the floor in the scale drawing

Mice21 [21]

Answer:

Step-by-step explanation:

Since 24 is the original length, you would have to see what number to divide by to get 6.

24 divided by 4 is 6.

Now we know that 1/4 is the scale factor, so apply that to 32.

32 divided by 4 is 6

That's your answer!

Brainliest would v much be appreciated

5 0

3 years ago